Question

我整天都在尝试，但是找不到出路。

我有两个密码；第一个生成将用于调用API的AccessToken。我还解析了Json输出，以便只能显示AccessToken参数……这是代码；

<?php
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, "https://sandbox.monnify.com/api/v1/auth/login/");

curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);

curl_setopt($ch, CURLOPT_HEADER, FALSE);

curl_setopt($ch, CURLOPT_POST, TRUE);

curl_setopt($ch, CURLOPT_HTTPHEADER, array(

  "Content-Type: application/json",

  "Authorization: Basic TUtfVEVTVF9TQUY3SFI1RjNGOjRTWTZUTkw4Q0szVlBSU0JUSFRSRzJOOFhYRUdDNk5M"

));

$response = curl_exec($ch);

$token = json_decode($response, true);

$at = $token['responseBody'];

echo $at['accessToken'];

curl_close($ch);

上面的代码输出令牌。

现在，这是在下面发送请求的代码；

<?php
$curl = curl_init();

curl_setopt_array($curl, array(

  CURLOPT_URL => "https://sandbox.monnify.com/api/v1/bank-transfer/reserved-accounts/ogmic1",

  CURLOPT_RETURNTRANSFER => true,

  CURLOPT_ENCODING => "",

  CURLOPT_MAXREDIRS => 10,

  CURLOPT_TIMEOUT => 0,

  CURLOPT_FOLLOWLOCATION => true,

  CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,

  CURLOPT_CUSTOMREQUEST => "GET",

  CURLOPT_HTTPHEADER => array(

    "Authorization: Bearer eyJhbGciOiJSUzI1NiIsInR5cCI6IkpXVCJ9.eyJhdWQiOlsibW9ubmlmeS1wYXltZW50LWVuZ2luZSJdLCJzY29wZSI6WyJwcm9maWxlIl0sImV4cCI6MTYwMTE0MDA0MywiYXV0aG9yaXRpZXMiOlsiTVBFX1JFVFJJRVZFX1JFU0VSVkVEX0FDQ09VTlQiLCJNUEVfREVMRVRFX1JFU0VSVkVEX0FDQ09VTlQiLCJNUEVfUkVUUklFVkVfUkVTRVJWRURfQUNDT1VOVF9UUkFOU0FDVElPTlMiLCJNUEVfSU5JVElBTElaRV9QQVlNRU5UIiwiTVBFX1JFU0VSVkVfQUNDT1VOVCIsIk1QRV9DQU5fUkVUUklFVkVfVFJBTlNBQ1RJT04iXSwianRpIjoiNmQ0OTA0ZDQtMzNjYy00Y2NlLWI3OTgtODg3ZjdlOTEwM2JhIiwiY2xpZW50X2lkIjoiTUtfVEVTVF9TQUY3SFI1RjNGIn0.jqjtn8uyVxSL8oVPNHojMRzqiPx__xYTzoPCsi5IJgiXd184Nc6XSp7QaZlbav6NjXQAt8uuYWVuEqZpJoHJSJlvR-QbpV_pkx582EV0cGdTNzFAUgyrRYvWxmFmNeS-XBVk0-8labvDqyLHcpjfoT_FaiBylY2ek99G8WvXxnvLE1STY91blhMb3UCKBykDzVlmX0U6gvWd9Btgb1-Zb18Olt-GHmsYavBDSvSpptSiIleFPsZzL1O_u366DVMmGrCq-1iqYpBBRixU0uslTsp17VJfvHJUwciPSHDDaPK2iH6QP7Nv4jPYMNhs8MW7L67NYO9yohD9qfAOTyWv6g"

  ),

));

$response = curl_exec($curl);

$objs = json_decode($response, true);

$rp = $objs['responseBody'];
 
echo "<div class='dlmenu1'> <span style='background:#fff;color:#295f2d;font-size:13px;text-align:center;font-weight:bold;padding:2px;margin-right:3px;'>" .
$rp['accountNumber'] . "</span>";
echo "<span style='background:#fff;color:#295f2d;font-size:13px;text-align:center;font-weight:bold;padding:2px;margin-right:3px;'>(" . $rp['bankName'] . ")</span>";
echo "<span style='background:#fff;color:#295f2d;font-size:13px;text-align:center;padding:2px;margin-right:3px;'>"  . " - Instant Funding</span></div>";

curl_close($curl);

在如何将第一个代码中生成的AccessToken传递给第二个代码（这两个代码合在一起）时，我需要帮助，以便可以用作授权载体。我不介意两个代码是否可以组合。

谢谢

如何将生成的API令牌作为授权承载传递

0 个答案: