Question

我想在屏幕上显示图像。图像应该来自URL，而不是可绘制的。

代码在这里：

<ImageView android:id="@+id/ImageView01" android:src = "http://l.yimg.com/a/i/us/we/52/21.gif"
    android:layout_width="wrap_content" android:layout_height="wrap_content"></ImageView>

但它在编译时出错。

如何在Android中显示来自网址的图片？

Answer 1

您可以直接在网上显示图片而无需下载。请检查以下功能。它会将网络上的图像显示在图像视图中。

public static Drawable LoadImageFromWebOperations(String url) {
    try {
        InputStream is = (InputStream) new URL(url).getContent();
        Drawable d = Drawable.createFromStream(is, "src name");
        return d;
    } catch (Exception e) {
        return null;
    }
}

然后使用您活动中的代码将图片设置为imageview。

Answer 2

我尝试使用此代码为我工作，直接从网址获取图片

splash screen

在onCreate（）方法中使用

new DownloadImageTask（（ImageView）findViewById（R.id.image）） .execute（＆＃34; http://scoopak.com/wp-content/uploads/2013/06/free-hd-natural-wallpapers-download-for-pc.jpg＆＃34）;

Answer 3

你可以试试我在另一个问题中找到的。

Android, Make an image at a URL equal to ImageView's image

try {
  ImageView i = (ImageView)findViewById(R.id.image);
  Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL(imageUrl).getContent());
  i.setImageBitmap(bitmap); 
} catch (MalformedURLException e) {
  e.printStackTrace();
} catch (IOException e) {
  e.printStackTrace();
}

Answer 4

你可以试试Picasso，这真的很好，也很容易。不要忘记在清单中添加权限。

Picasso.with(context)
                     .load("http://ImageURL")
                     .resize(width,height)
                     .into(imageView );

您还可以在此处查看教程： Youtube / Github

Answer 5

简单的例子，
http://www.helloandroid.com/tutorials/how-download-fileimage-url-your-device

您必须使用httpClient并下载图像（如果需要，将其缓存），

提供用于在listview中显示图像的解决方案，基本上是相同的代码（检查从url设置imageview的代码）以进行显示。

Lazy load of images in ListView

Answer 6

我使用以下代码重试了URL中的图像并存储在我的SD卡上：

public String Downloadfromurl(String Url)
{

 String filepath=null;

 try {

  URL url = new URL(Url);

  //create the new connection

  HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();

  //set up some things on the connection
  urlConnection.setRequestMethod("GET");

  urlConnection.setDoOutput(true); 

   //and connect!

  urlConnection.connect();

  //set the path where we want to save the file
  //in this case, going to save it on the root directory of the
  //sd card.

  folder = new File(Environment.getExternalStorageDirectory().toString()+"/img");

  folder.mkdirs();

  //create a new file, specifying the path, and the filename
  //which we want to save the file as.

  String filename= "page"+no+".PNG";   

  file = new File(folder,filename);

  if(file.createNewFile())

  {

   file.createNewFile();

  }

  //this will be used to write the downloaded data into the file we created
  FileOutputStream fileOutput = new FileOutputStream(file);

  //this will be used in reading the data from the internet
  InputStream inputStream = urlConnection.getInputStream();

  //this is the total size of the file
  int totalSize = urlConnection.getContentLength();
  //variable to store total downloaded bytes
  int downloadedSize = 0;

  //create a buffer...
  byte[] buffer = new byte[1024];
  int bufferLength = 0; //used to store a temporary size of the buffer

  //now, read through the input buffer and write the contents to the file
  while ( (bufferLength = inputStream.read(buffer)) > 0 ) {
   //add the data in the buffer to the file in the file output stream (the file on the sd card
   fileOutput.write(buffer, 0, bufferLength);
   //add up the size so we know how much is downloaded
   downloadedSize += bufferLength;
   //this is where you would do something to report the prgress, like this maybe
   Log.i("Progress:","downloadedSize:"+downloadedSize+"totalSize:"+ totalSize) ;
  }
  //close the output stream when done
  fileOutput.close();
  if(downloadedSize==totalSize)  
      filepath=file.getPath();

 //catch some possible errors...
 } catch (MalformedURLException e) {
  e.printStackTrace();
 } catch (IOException e) {
  filepath=null;
  e.printStackTrace();
 }
 Log.i("filepath:"," "+filepath) ;


 return filepath;

}

Answer 7

InputStream URLcontent = (InputStream) new URL(url).getContent();
Drawable image = Drawable.createFromStream(URLcontent, "your source link");

这对我有用

Answer 8

使用ASyncTask编写代码以进行http处理。

Bitmap b;
ImageView img;
......
try
    {
        URL url = new URL("http://10.119.120.10:80/img.jpg");
        InputStream is = new BufferedInputStream(url.openStream());
        b = BitmapFactory.decodeStream(is);
    } catch(Exception e){}
......
img.setImageBitmap(b);

Answer 9

我也有同样的问题。我测试这段代码并且效果很好。此代码从URL获取图像并放入 - ＆＃34; bmpImage＆＃34;

URL url = new URL("http://your URL");
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setReadTimeout(60000 /* milliseconds */);
            conn.setConnectTimeout(65000 /* milliseconds */);
            conn.setRequestMethod("GET");
            conn.setDoInput(true);
            conn.connect();
            int response = conn.getResponseCode();
            //Log.d(TAG, "The response is: " + response);
            is = conn.getInputStream();


            BufferedInputStream bufferedInputStream = new BufferedInputStream(is);

            Bitmap bmpImage = BitmapFactory.decodeStream(bufferedInputStream);

Answer 10

您可以简单地使用Glide API。它避免了所有样板代码，并且可以用两行代码来完成任务。您引用此链接https://blog.mindorks.com/downloading-and-showing-image-with-glide-library-in-android。享受

如何在Android上显示来自URL的图像

10 个答案: