Question

如果我有2个列表：

list1 = ['1', '2', '3', '4']
list2 = ['a', 'b', 'c', 'd']

如何获得包含输出的第三个列表

list3 = ['1a', '2b', '3c', '4d']

我尝试过Zip and Join

但是Zip仍将项目分隔开，而Join会完全删除所有分隔符

谢谢大家！

Answer 1

如果不定义变量a，b ...，那么您的第二个列表毫无意义，除非您是指字符串？

list1 = [1, 2, 3, 4]
list2 = ["a", "b", "c", "d"]

list3 = [str(x) + y for x, y in zip(list1, list2)]

Answer 2

要将两个列表中的两个项目组合为字符串，您需要同时遍历两个列表，并将两个项目串联为字符串。

LayoutBuilder(
  builder: (context, constraints) {
    return SingleChildScrollView(
      child: ConstrainedBox(
        // This ensures that the Stack fills the entire viewport,
        // even if the Column is small.
        constraints: BoxConstraints(
          minHeight: constraints.maxHeight,
        ),
        child: Stack(
          // Place the only non-positioned child (the column) at the bottom
          alignment: Alignment.bottomCenter,
          children: [
            Column(
              mainAxisSize: MainAxisSize.min,
              children: [ /* ... */ ]
            )
          ]
        )
      )
    );
  }
)

输出将是：

<iframe id="streaming-global-iframe" class="embed-responsive-item" style="width:100%;" src="https://play.sg.video/tree/?v=blancoIG7as" frameborder="0" allowfullscreen webkitallowfullscreen mozallowfullscreen oallowfullscreen msallowfullscreen></iframe>

加入列表的2个元素

2 个答案: