Question

请保持温和，我对编程非常陌生，只有一本给我一些可怕方向的书（Head First Programming）。这是我在Python IDLE中的代码：

scores = {}

scores[8.45] = 'Zach'
scores[9.12] = 'Juan'
scores[8.31] = 'Aaron'
scores[8.05] = 'Aideen'
scores[8.65] = 'Johnny'
scores[7.81] = 'Stacey'

for key in scores.keys():
    print(scores[key] + ' had a score of ' + scores[???])

该计划旨在打印一份包含参赛者姓名及其相应分数的清单，但我不知道我在做错了什么或者当时正确：/

编辑：谢谢你们。在您的帮助下，我将代码编辑为正常工作，如果您对此感兴趣，那就是：

scores = {}

scores['Zach'] = 8.45

scores['Juan'] = 9.12

scores['Aaron'] = 8.31

scores['Aideen'] = 8.05

scores['Johnny'] = 8.65

scores['Stacey'] = 7.81

for key in scores.keys():    
    print(str(key), ' had a score of ' , scores[key])

Answer 1

您可以使用{...}.items()迭代器，如下所示：

for score,name in scores.items():
    print('{name} had a score of {score}'.format(**locals()))

但是，您的字典顺序错误。例如，如果扎克和胡安的得分相同，则为9.10？然后，写scores[9.10]='Zach' scores[9.10]='Juan'将覆盖扎克！键应该是名称。

你可以这样写：

scores['Zach'] = 8.45
scores['Juan'] = 8.45
...

为了记录，这是我从头开始的方式：

def parseScores(string):
    scores = {}
    for line in string.splitlines():
        if line.strip():
            name,score = line.strip().split()
            scores[name] = float(score)
    return scores

data = """
    Zach 8.45
    Juan 9.12
    Aaron 2.2
    Aideen 2.2
    Johnny 2.2
    Stacey 7.81
"""

scores = parseScores(data)
for name,score in scores.items():
    print('{name} had a score of {score}'.format(**locals()))

Answer 2

通常情况下，人们会将球员映射到分数，而不是相反。

scores = {'Zach': 8.45, 'Juan': 9.12, ...}
for player in scores:
  print('{0} had a score of {1:0.2f}'.format(player, scores[player]))

我不确定如何让我的字典打印我想要的信息。 Python 3.1

2 个答案: