我有两个列表项,我想根据不匹配的项生成一个列表。这是我正在尝试做的事情:
from __future__ import print_function
import os
mainline_list = ['one', 'two', 'three', 'four']
non_main_list = ['two', 'seven', 'six', 'four', 'four-3.1', 'new_three']
itemized_list = [item for item in non_main_list if item not in mainline_list]
print(itemized_list)
退货是
['seven', 'six', 'four-3.1', 'new_three']
我想要的是:
['seven', 'six']
答案 0 :(得分:1)
不需要正则表达式,可以使用all()
内置函数:
mainline_list = ['one', 'two', 'three', 'four']
non_main_list = ['two', 'seven', 'six', 'four', 'four-3.1', 'new_three']
print([item for item in non_main_list if all(i not in item for i in mainline_list)])
打印:
['seven', 'six']