Question

我在字符串中有一个完整的XML文档，我需要将其转换为XML文档并解析文档中的标记

Answer 1

要在XML文件中查找节点，您可以使用XPath表达式。方法XmlNode.SelectNodes返回由XPath字符串选择的节点列表。方法XmlNode.SelectSingleNode查找与XPath字符串匹配的第一个节点。

XML：

<Names>
    <Name>
        <FirstName>John</FirstName>
        <LastName>Smith</LastName>
    </Name>
    <Name>
        <FirstName>James</FirstName>
        <LastName>White</LastName>
    </Name>
</Names>

CODE：

XmlDocument xml = new XmlDocument();
xml.LoadXml(myXmlString); // suppose that myXmlString contains "<Names>...</Names>"

XmlNodeList xnList = xml.SelectNodes("/Names/Name");
foreach (XmlNode xn in xnList)
{
  string firstName = xn["FirstName"].InnerText;
  string lastName = xn["LastName"].InnerText;
  Console.WriteLine("Name: {0} {1}", firstName, lastName);
}

Answer 2

使用Linq to xml

添加对System.Xml.Linq的引用

并使用

XDocument.Parse(string xmlString)

编辑：Sample跟随，xml数据（TestConfig.xml）..

<?xml version="1.0"?>
<Tests>
  <Test TestId="0001" TestType="CMD">
    <Name>Convert number to string</Name>
    <CommandLine>Examp1.EXE</CommandLine>
    <Input>1</Input>
    <Output>One</Output>
  </Test>
  <Test TestId="0002" TestType="CMD">
    <Name>Find succeeding characters</Name>
    <CommandLine>Examp2.EXE</CommandLine>
    <Input>abc</Input>
    <Output>def</Output>
  </Test>
  <Test TestId="0003" TestType="GUI">
    <Name>Convert multiple numbers to strings</Name>
    <CommandLine>Examp2.EXE /Verbose</CommandLine>
    <Input>123</Input>
    <Output>One Two Three</Output>
  </Test>
  <Test TestId="0004" TestType="GUI">
    <Name>Find correlated key</Name>
    <CommandLine>Examp3.EXE</CommandLine>
    <Input>a1</Input>
    <Output>b1</Output>
  </Test>
  <Test TestId="0005" TestType="GUI">
    <Name>Count characters</Name>
    <CommandLine>FinalExamp.EXE</CommandLine>
    <Input>This is a test</Input>
    <Output>14</Output>
  </Test>
  <Test TestId="0006" TestType="GUI">
    <Name>Another Test</Name>
    <CommandLine>Examp2.EXE</CommandLine>
    <Input>Test Input</Input>
    <Output>10</Output>
  </Test>
</Tests>

C＃用法......

XElement root = XElement.Load("TestConfig.xml");
IEnumerable<XElement> tests =
    from el in root.Elements("Test")
    where (string)el.Element("CommandLine") == "Examp2.EXE"
    select el;
foreach (XElement el in tests)
    Console.WriteLine((string)el.Attribute("TestId"));

此代码生成以下输出：技术 0006

Answer 3

根据您希望的文档类型，您可以使用XmlDocument.LoadXml或XDocument.Load。

Answer 4

试试这段代码：

var myXmlDocument = new XmlDocument();
myXmlDocument.LoadXml(theString);

XML字符串到XML文档

4 个答案: