Question

我需要在b_id中找到重复最长时间的值。例如，下表的查询应该返回40（n.b。，查询应返回单个值）

| b_id | s_id | doi        | dos        | charge |
+------+------+------------+------------+--------+
|   10 |    3 | 0000-00-00 | 0000-00-00 |    200 |
|   10 |    2 | 0000-00-00 | 0000-00-00 |    200 |
|   20 |    1 | 0000-00-00 | 0000-00-00 |    200 |
|   30 |    2 | 0000-00-00 | 0000-00-00 |    200 |
|   40 |    4 | 0000-00-00 | 0000-00-00 |    200 |
|   40 |    5 | 0000-00-00 | 0000-00-00 |    200 |
|   70 |    5 | 0000-00-00 | 0000-00-00 |    200 |
|   40 |    4 | 0000-00-00 | 0000-00-00 |    200 |

Answer 1

SELECT TOP 1 COUNT(*) as total FROM dbo.Table GROUP BY b_id ORDER BY total DESC

编辑： ups，mysql等价物：

SELECT COUNT(*) as total FROM dbo.Table GROUP BY b_id ORDER BY total DESC LIMIT 1

EDIT2：评论之后：

SELECT b_id FROM dbo.Table GROUP BY b_id ORDER BY COUNT(b_id) DESC LIMIT 1

mysql查询查找重复最长时间的值

1 个答案: