我试图在侧栏中显示当前页面的类别及其子类别。标题应该是当前类别的名称,并且还应该链接到当前类别。在边栏中可以找到我要实现的目标的示例:https://food52.com/shop/pantry
以我当前的网站为例:https://farmtofrank.wpengine.com/product-category/prepared-foods/
这是我到目前为止创建的代码:
<?php
$terms = get_terms([
'taxonomy' => get_queried_object()->taxonomy,
'parent' => get_queried_object_id(),
]);
global $post;
$terms = get_the_terms( $post->ID, 'product_cat' );
echo '<div>';
foreach ( $terms as $term) {
echo '<p class="filters"><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></p>';
}
echo '</div>';
?>
它可以工作,但是将父链接放在列表的底部。如何将父链接保持在子类别上方的顶部?
答案 0 :(得分:3)
我想这与产品类别归档页面有关。在这种情况下,您距离很近,请尝试:
$queried_object = get_queried_object();
if ( is_product_category() && is_a($queried_object, 'WP_Term') ) {
$taxonomy = $queried_object->taxonomy;
echo '<h2 class="shop__sidebar-heading">
<a href="' . get_term_link( $queried_object ) . '">' . $queried_object->name . '</a>
</h2>';
$children_terms = get_terms(['taxonomy' => $taxonomy, 'parent' => $queried_object->term_id]);
if ( ! empty($children_terms) ) {
echo '<ul class="'.$queried_object->slug.' child-terms">';
// Loop through children terms
foreach ( $children_terms as $term) {
echo '<li class="filters"><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></li>';
}
echo '</ul>';
}
}
经过测试,可以正常工作。它将需要一些样式(CSS)。