Flutter:按日期读取和合并Firestore数据

时间:2020-09-22 08:53:48

标签: flutter google-cloud-firestore

我正在寻找一种按日期合并从Cloud Firestore读取的数据的方法。我的目的是从Cloud Firestore中读取所有文档,然后将某个日期的所有文档放在一个ExpansionTile下。即每个日期一个ExpansionTile,每个ExpansionTile可能包含许多单独的文件,具体取决于当天上传了多少文件。

我从Cloud Firestore读取数据没有问题,但是一旦掌握了信息,我就很难弄清楚如何按日期组织和合并文档。请记住,会有多个不同的日期,并且每个日期都有不同数量的文件。

如下图所示,我目前拥有三个具有相同日期的文档,因此在应用程序中创建它们时,三个ExpansionTiles也不同。我希望将这三个转换成一个ExpansionTile

enter image description here

我目前正在使用flutter_bloc软件包按日期从Cloud Firestore中读取数据:

    //Retrieves firebase data of all orders done in the past
  Stream<OrderHistoryState> _loadOrderHistory() async* {
    try {
      _orderSubscription?.cancel();

      var orderHistory = Firestore.instance
          .collection('orders')
          .orderBy('date', descending: true);

      _orderSubscription = orderHistory.snapshots().listen(
        (event) {
          if (event.documents.length > 0) {
            add(OrderHistoryUpdate(
              documents: event.documents,
            ));
          } else {
            print("No Order to Load");
            add(NoOrderHistory());
          }
        },
      );
    } catch (e) {
      print("Error with Tracking Status, $e");
          add(ErrorOrderHistory());
        }  
}

1 个答案:

答案 0 :(得分:1)

对于那些可能好奇的人,这是我解决问题的方法。可能会花很多时间,所以任何缩短/改进它的建议仍然值得赞赏:

                  //Make sure that there are documents within firebase
                  if (state.orderHistoryDocuments.length != 0) {
                    //Adding the first document manually so that
                    //the forloop section has something to compare dates
                    //This listForEachDate is for storing a collection
                    //of all documents of one date
                    listForEachDate = [state.orderHistoryDocuments[0].data];
                    //listOfDateLists is a list of all listForEachDate
                    //This gives us a list of lists with the documents
                    //separated by date i.e.
                    //[[date1, date1], [date2], [date3, date3, date3], etc]
                    listOfDateLists = [];

                    //i = 1 because index 0 already added above
                    for (int i = 1;
                        i < state.orderHistoryDocuments.length;
                        i++) {
                      //If the current index's date matches that of the previous
                      //index's date, then add it to the listForEachDate
                      if (state.orderHistoryDocuments[i]
                              .data["dateCreated"] ==
                          state.orderHistoryDocuments[i - 1]
                              .data["dateCreated"]) {
                        listForEachDate
                            .add(state.orderHistoryDocuments[i].data);
                        //If [index]date does not match [index - 1]date
                        //Then add the current listForEachDate to the
                        //listOfDateLists i.e. add sublist to list of lists
                      } else {
                        listOfDateLists.add(listForEachDate);
                        //Clear the listForEachDate so that we can create
                        //a new clean list of new dates
                        listForEachDate = [];
                        //Add the new date to the listForEachDate
                        //so that the process can start again
                        listForEachDate
                            .add(state.orderHistoryDocuments[i].data);
                      }
                    }
                    //Once the document has been iterated through,
                    //Add to the big list.
                    listOfDateLists.add(listForEachDate);
                  }