Question

我需要的是一个SQL查询，它可以报告来自聚合表和单数表的数据。我目前的数据库如下。

CREATE TABLE IF NOT EXISTS `faults_days` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `employee_id` int(11) NOT NULL,
    `day_date` date NOT NULL,
    `actioned_calls_out` int(11) NOT NULL,
    `actioned_calls_in` int(11) NOT NULL,
    `actioned_tickets` int(11) NOT NULL,
)

CREATE TABLE IF NOT EXISTS `faults_departments` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `name` varchar(40) NOT NULL,
)

CREATE TABLE IF NOT EXISTS `faults_employees` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `team_id` int(11) NOT NULL,
    `name` varchar(127) NOT NULL,
)

CREATE TABLE IF NOT EXISTS `faults_qos` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `qos_date` datetime NOT NULL,
    `employee_id` int(11) NOT NULL,
    `score` double NOT NULL,
)

CREATE TABLE IF NOT EXISTS `faults_teams` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `department_id` int(11) NOT NULL,
    `name` varchar(40) NOT NULL,
)

Day中的一行跟踪单个员工一天的表现（所接听的电话数，所处理的电话票数）。 Qos是衡量一天员工素质的指标（每天可以有多个Qos - 我需要获得的是平均分数）。此外，Qos可以在员工在数据库中没有性能条目的那天执行，并且仍然需要在报告中显示。

所需的最终结果是4份报告，显示按不同列分组的员工绩效。单个员工每天的绩效细分，员工在一段时间内的总体绩效，团队在一段时间内的表现，以及整个部门在一段时间内的表现。

我的问题是，我当前的查询有点复杂，需要对Day数据和Qos数据进行两次单独的查询。然后我的PHP应用程序在输出报告之前合并数据。 我想要的是一个单一查询，它可以返回总体效果和平均质量得分。

我必须向员工展示的当前查询是：

SELECT  
    `Employee`.`name` ,  
    `Team`.`name` , 
    `Department`.`name` , 
    SUM(  `Day`.`actioned_calls_in` ) + SUM(  `Day`.`actioned_calls_out` ) , 
    SUM(  `Day`.`actioned_tickets` ) 
FROM  
    `faults_days` AS  `Day` 
JOIN  
    `faults_employees` AS  `Employee` ON  `Day`.`employee_id` =  `Employee`.`id` 
JOIN  
    `faults_teams` AS  `Team` ON  `Employee`.`team_id` =  `Team`.`id` 
JOIN  
    `faults_departments` AS  `Department` ON  `Team`.`department_id` =  `Department`.`id` 
WHERE  
    `Day`.`day_date` >=  '2011-06-01'
    AND  `Day`.`day_date` <=  '2011-06-07'
GROUP BY  `Employee`.`id` 
WITH ROLLUP

和

SELECT  
    `Employee`.`name` ,  
    `Team`.`name` ,  
    `Department`.`name` , 
    COUNT(  `Qos`.`score` ) , 
    AVG(  `Qos`.`score` ) 
FROM  
    `faults_qos` AS  `Qos` 
JOIN  
    `faults_employees` AS  `Employee` ON  `Qos`.`employee_id` =  `Employee`.`id` 
JOIN  
    `faults_teams` AS  `Team` ON  `Employee`.`team_id` =  `Team`.`id` 
JOIN  
    `faults_departments` AS  `Department` ON  `Team`.`department_id` =  `Department`.`id` 
WHERE  
    `Qos`.`qos_date` >=  '2011-06-01'
    AND  `Qos`.`qos_date` <=  '2011-06-07'
GROUP BY  `Employee`.`id` 
WITH ROLLUP

我也尝试过简单地加入Qos表，但由于它返回了多行，因此会导致SUM()总计混乱，并且由于缺少FULL OUTER JOIN功能而出现问题。

修改我用这个做了一些小的进展。看起来使用子查询是可行的方法，但我所做的一切都是纯粹的猜测。这是我到目前为止所得到的，如果Day和Qos表中都有一个条目，它只显示一行，这不是我想要的，我不知道如何扩展它包括上述各种分组。

SELECT  
    `Employee`.`name` ,  
    `Team`.`name` , 
    `Department`.`name`,
    `Day`.`Calls`,
    `Day`.`Tickets`,
    `Qos`.`NumQos`,
    `Qos`.`Score`
FROM `faults_employees` AS  `Employee` 
JOIN  
    `faults_teams` AS  `Team` ON  `Employee`.`team_id` =  `Team`.`id` 
JOIN  
    `faults_departments` AS  `Department` ON  `Team`.`department_id` =  `Department`.`id` 
JOIN
    (SELECT
        `Day`.`employee_id` AS `eid`,
        SUM(`Day`.`actioned_calls_in`) + SUM(`Day`.`actioned_calls_out`) AS `Calls`, 
        SUM(`Day`.`actioned_tickets`) AS `Tickets`
    FROM `faults_days` AS `Day`
    WHERE
        `Day`.`day_date` = '2011-03-02'
    GROUP BY `Day`.`employee_id`
    ) AS `Day`
    ON `Day`.`eid` = `Employee`.`id`
JOIN
    (SELECT
        `Qos`.`employee_id` AS qid,
        COUNT(`Qos`.`id`) AS `NumQos`,
        AVG(`Qos`.`score`) AS `Score`
    FROM `faults_qos` AS `Qos`
    WHERE
        `Qos`.`qos_date` = '2011-03-02'
    GROUP BY `Qos`.`employee_id`
    ) AS `Qos`
    ON `Qos`.`qid` = `Employee`.`id`
GROUP BY `Employee`.`id`

Answer 1

您确实需要left join和fault_qos子查询中的fault_days。即使在一个或两个中没有相应的行，这也会给你一个结果。 left join表示该值在连接左边的表中是必需的，而不是右边的那个。我没有对此进行测试，现在已经很晚了，所以我可能没有想清楚，但是如果你将查询改为此，它应该可以工作：

SELECT  
    `Employee`.`name` ,  
    `Team`.`name` , 
    `Department`.`name`,
    `Day`.`Calls`,
    `Day`.`Tickets`,
    `Qos`.`NumQos`,
    `Qos`.`Score`
FROM `faults_employees` AS  `Employee` 
JOIN  
    `faults_teams` AS  `Team` ON  `Employee`.`team_id` =  `Team`.`id` 
JOIN  
    `faults_departments` AS  `Department` ON  `Team`.`department_id` =  `Department`.`id` 
LEFT JOIN
    (SELECT
        `Day`.`employee_id` AS `eid`,
        SUM(`Day`.`actioned_calls_in`) + SUM(`Day`.`actioned_calls_out`) AS `Calls`, 
        SUM(`Day`.`actioned_tickets`) AS `Tickets`
    FROM `faults_days` AS `Day`
    WHERE
        `Day`.`day_date` = '2011-03-02'
    GROUP BY `Day`.`employee_id`
    ) AS `Day`
    ON `Day`.`eid` = `Employee`.`id`
LEFT JOIN
    (SELECT
        `Qos`.`employee_id` AS qid,
        COUNT(`Qos`.`id`) AS `NumQos`,
        AVG(`Qos`.`score`) AS `Score`
    FROM `faults_qos` AS `Qos`
    WHERE
        `Qos`.`qos_date` = '2011-03-02'
    GROUP BY `Qos`.`employee_id`
    ) AS `Qos`
    ON `Qos`.`qid` = `Employee`.`id`
GROUP BY `Employee`.`id`

MySQL加入涉及聚合数据

1 个答案: