Question

我想显示一个通知，当用户点击它时，应该播放一个声音文件。

在Android Studio中，我已将文件test.mp3复制到文件夹app\res\raw中。通知是通过以下代码发出的：

Resources resources = getResources();                                                 
Uri uri = new Uri.Builder()                                                           
        .scheme(ContentResolver.SCHEME_ANDROID_RESOURCE)                              
        .authority(resources.getResourcePackageName(R.raw.test))                      
        .appendPath(resources.getResourceTypeName(R.raw.test))                        
        .appendPath(resources.getResourceEntryName(R.raw.test))                       
        .build();                                                                     
                                                                                      
Intent playSoundIntent = new Intent();                                                
playSoundIntent.setAction(android.content.Intent.ACTION_VIEW);                        
playSoundIntent.setDataAndType(uri, "audio/*");                                       
                                                                                      
PendingIntent pendingIntent = PendingIntent.getActivity(this, 0,                      
        playSoundIntent, 0);                                                          
                                                                                      
NotificationCompat.Builder builder = new NotificationCompat.Builder(this,             
        MainActivity.notificationChannelId)                                           
        .setSmallIcon(android.R.drawable.ic_media_play)                               
        .setContentTitle(getResources().getString(R.string.app_name))                 
        .setContentText("Tap to play sound!")                                         
        .setContentIntent(pendingIntent)                                              
        .setPriority(NotificationCompat.PRIORITY_DEFAULT)                             
        .setAutoCancel(true);                                                         

NotificationManagerCompat notificationManager = NotificationManagerCompat.from(this);

notificationManager.notify(12345678, builder.build());

它无法正常工作。显示该通知，如果我点击它，它会消失（由于setAutoCancel(true)）。但是我听不到声音。为什么？

我该如何调试？

非常感谢您！

Answer 1

我通过创建这样的意图来管理它：

<?php
$host = "localhost";
$user = "root";
$password = "";
$dbname = "odcinki";

$conn = mysqli_connect($host,$user,$password,$dbname);
if (mysqli_connect_errno()) {echo "Brak polaczenia" . mysqli_connect_error();}

$postID = get_queried_object_id();
   
   $current_user =  wp_get_current_user();
   
   $current= $current_user->ID ;

$sql = "SELECT lastname FROM `$current` WHERE id = '$postID'";

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($result);
$keepchecked= $row['lastname'];

}







?>

 <?php if ( is_user_logged_in() ) {     ?> Status: <input type="checkbox" name = "seks" value ="1" id="checkboxtest" <?php echo ($keepchecked == "YES") ? 'checked="checked"' : ''; ?> >
<?php
}
?>
<script type="text/javascript">
$(document).ready(function(e) {
$('#checkboxtest').change(function(){
   var checkboxstatus = "";
   var postID = "<?php echo $postID;?>";
    if( $('#checkboxtest').prop('checked') )
       {checkboxstatus = "YES";}
       else
       {checkboxstatus = "NO";}
$.ajax({
        type: "POST",
        url: "checkboxtestbackend.php",
        data: {checkboxstatus: checkboxstatus, postID : postID},
        success: function(result) {
                console.log('the data was successfully sent to the server');
            }
        })
        
});
});
    ?>

并添加活动：

Intent playSoundIntent = new Intent(this, PlaySoundActivity.class);

PendingIntent pendingIntent = PendingIntent.getActivity(this, 0, playSoundIntent, 0);

尽管这可行，但是我仍然对为什么前一种方法行不通感兴趣。我已经看到很多类似的代码片段。而且我仍然想知道如何调试以前的方法来理解错误。有人可以帮我吗？

在点击时如何创建播放音频文件的通知？

1 个答案: