如何在按下按钮时关闭弹出窗口并在打开弹出窗口的窗口上启动回发？

Question

见上文......

Answer 1

你应该能够在window.parent中调用函数。

<script type="text/javascript">
    function closeThisPopupWindow()
    {
        if (window.parent && window.parent.callBack)
            window.parent.callBack();
        window.close();
    }
</script>

显然你需要将closeThisPopupWindow函数附加到你的按钮。

Answer 2

尝试这样的事情：

parent.document.getElementById('btnSubmit').click();; // submit the parent form
self.close(); // close the current window

Answer 3

我会按下弹出窗口的按钮

ClientScript.RegisterStartupScript(typeof(string), "auto_refreshparent", @" window.opener.location.reload(); ", true);
ClientScript.RegisterStartupScript(typeof(Page), "ThatsAllFolks", "window.close();", true);

Answer 4

string windowArgs =“toolbar = no，menubar = no，location = no，width = 620，height = 500，scrollbars = yes，resizable = yes，modal = yes”;         string newWindowUrl =“MarketShotPreview.aspx”;         string javaScript =          “\ n”+          “\ n”+          “\ n” 个;         ClientScript.RegisterStartupScript（typeof（System.Web.UI.Page），“Popup”，javaScript）;