Question

我正在尝试运行这个正常工作的动画，但我希望最后一个数字留在屏幕上。目前它通过数组运行然后消失..无论如何停止传递的数字上的动画？

- (void)playAnimationToNumber:(int)number{

    NSMutableArray *imagesForAnimation = [[NSMutableArray alloc] initWithCapacity:0];


    for (int counter=1; counter<=number; counter++) {

        NSString *imageNameForFirstNumber = [NSString stringWithFormat:@"Flap%i.png", counter];
        [imagesForAnimation addObject:[UIImage imageNamed:@"FlapMoving1.png"]];
        [imagesForAnimation addObject:[UIImage imageNamed:@"FlapMoving2.png"]];
        [imagesForAnimation addObject:[UIImage imageNamed:imageNameForFirstNumber]];
    }
    animationArray.animationImages = [NSArray arrayWithArray:imagesForAnimation];        

    animationArray.animationDuration = 1.2;
    animationArray.animationRepeatCount = 1;
    [animationArray startAnimating];
    [self.view addSubview:animationArray];
    [imagesForAnimation release];


}

Answer 1

根据UIImageView startAnimating: How do you get it to stop on the last image in the series?，动画结束后显示的图像在“image”属性中给出。所以这样的事情应该可以解决问题：

animationArray.image = [imagesForAnimation lastObject];

Answer 2

        for (int counter=1; counter<number; counter++) {
        ...
        }
        [imagesForAnimation addObject:[UIImage imageNamed:@"FlapMoving1.png"]];
        [imagesForAnimation addObject:[UIImage imageNamed:[NSString stringWithFormat:@"Flap%i.png", number]]];

迭代到所有图像，但最后一个（计数器），然后将最后一个图像添加到动画数组应该有所帮助。告诉我它是如何工作的。

如何在最后一张图片上停止我的动画？

2 个答案: