我要实现的是将每个DISTINCT名称值的所有DISTINCT姓氏值串联起来。
我所管理的是DISTINCT名称值的串联,但是不幸的是所有姓氏值。
下面是我的代码:
SELECT DISTINCT ST2.[Name],
SUBSTRING(
(
SELECT ','+ST1.Surname AS [text()]
FROM [Ext_Names] ST1
WHERE ST1.[Name] = ST2.[Name]
ORDER BY ST1.[Name]
FOR XML PATH ('')
), 2, 1000) [Surname]
FROM [Ext_Names] ST2
样本数据
结果
所需的输出
答案 0 :(得分:3)
您需要先选择不同的值,然后再进行汇总。如果您运行的是SQL Server 2017或更高版本,则可以使用string_agg()
:
select name, string_agg(surname, ',') within group (order by surname) surnames
from (select distinct name, surname from ext_names) t
group by name
答案 1 :(得分:0)
您可以做到这一点。
SELECT DISTINCT ST2.[Name], SUBSTRING((SELECT ','+ T.Surename AS [text()] FROM (SELECT DISTINCT ST1.Surename FROM Ext_Names ST1 WHERE ST1.Name = ST2.Name ) T ORDER BY T.Surename FOR XML PATH('')),2,1000) [SureEname]
FROM Ext_Names ST2