这是我目前没有加入的声明
$s1 = "SELECT *
FROM states
WHERE
statecode='".intval($getStateCode)."'
";
$s2 = "SELECT *
FROM county
WHERE
statecode='".intval($getStateCode)."'
AND
countycode='".intval($getCountyCode)."'
";
$s3 = "SELECT *
FROM town
WHERE
statecode='".intval($getStateCode)."'
AND
countycode='".intval($getCountyCode)."'
AND
towncode='".intval($getTownCode)."'";
$s4 = "SELECT *
FROM villages
WHERE
statecode='".intval($getStateCode)."'
AND
countycode='".intval($getCountyCode)."'
AND
towncode='".intval($getTownCode)."'
AND
villagecode='".intval($getVillageCode)."'";
可以在一个声明中加入我的所有表吗?让我知道。
答案 0 :(得分:3)
<?php
$query = "SELECT *
FROM state s
JOIN county c ON s.statecode = c.statecode
JOIN town t ON s.statecode = t.statecode AND c.countycode = t.countycode
JOIN villages v ON s.statecode = v.statecode AND c.countycode = v.countycode AND t.towncode = v.towncode
WHERE
s.statecode='".intval($getStateCode)."'
AND
c.countycode='".intval($getCountyCode)."'
AND
t.towncode='".intval($getTownCode)."'
AND
v.villagecode='".intval($getVillageCode)."'";
答案 1 :(得分:1)
这应该让你开始:
SELECT * FROM state s
INNER JOIN county c ON c.statecode = s.statecode
INNER JOIN town t ON t.statecode = s.statecode AND t.countycode = c.countycode
INNER JOIN villages v ON v.statecode = s.statecode AND v.countycode = c.countycode AND v.towncode = t.towncode
答案 2 :(得分:0)
你可以试试这个:
$sql = "select * from villages V
join town T on T.towncode=V.towncode
join county C on C.countycode=V.countycode
join state S on S.statecode=V.statecode
where V.statecode='".intval($getStateCode)."'
and V.countycode='".intval($getCountyCode)."'
and V.towncode='".intval($getTownCode)."'
and V.villagecode='".intval($getVillageCode)."'";