如果前行在熊猫中相同，则删除行

Question

我有一个数据框，并且如果前一行相同，想删除该行。

我当前的代码：

df = pd.read_csv("MyCSV.csv", ";")
df_2 = df.loc[:,['A', 'B', 'C', 'D']]
for i in df_2.itertuples():
    if df_2[i] == df_2[i+1]:
    print(df)

我有这个输入数据框：

这是我想要的输出：

用于重新创建输入数据框的代码：

df = pd.DataFrame({'time': [0,1,2,3,4,5,9,10,11,12,13,14,15],
                   'A': [0.0] * 13, 
                   'B': [0.0,0.0,0.0,0.0,0.00000813,0.00000813,0.0, 0.0,0.0,0.0,0.0,0.00000813,0.00000813], 
                   'C': [0.0000109,0.0000109,0.0,0.0,0.0,0.0,0.0,0.0,0.0000109,0.0000109,0.0,0.0,0.0],
                   'D': [0.00000222,0.00000222,0.0,0.0,0.0,0.0,0.0,0.0,0.00000222,0.00000222,0.0,0.0,0.0]
                  })

Answer 1

您可以使用shift进行以下操作：

cols = ['A', 'B', 'C', 'D']
df.loc[(df[cols].shift(-1) == df[cols]).all(1)]

结果数据框：

time    A         B         C         D
   0  0.0  0.000000  0.000011  0.000002
   2  0.0  0.000000  0.000000  0.000000
   4  0.0  0.000008  0.000000  0.000000
   9  0.0  0.000000  0.000000  0.000000
  11  0.0  0.000000  0.000011  0.000002
  14  0.0  0.000008  0.000000  0.000000