Question

我正在尝试使用sql中的合并功能将存储过程的参数值插入表中。参数由数据库和模式名称组成。我已经为此编写了一个存储过程，但是，我不知道我在哪里做错了。这是我的尝试：

CREATE TABLE TABL(DBName VARCHAR, SCName VARCHAR) // creating table

REATE OR REPLACE PROCEDURE repo(DB VARCHAR,SC VARCHAR) //need to push DB, SC INTO TABL
    RETURNS type
    LANGUAGE JAVASCRIPT
    AS
    $$      
       //Inserting parameters into table as values but didn;t work  
        var sql_command = "merge TABL as t using (SELECT +"DB"+ as database,+"SC"  as schema) as s on t.DBName = s.DB and t.SCName = s.schema when matched then update set t.DBName = t.DBName when not matched then insert (DBName, SCName) VALUES ('"+DB+"','"+SC +"')";
        snowflake.execute({sqlText: sql_command});

    return type;
    $$;

Answer 1

您可以使用绑定：

CREATE TABLE TABL(DBName VARCHAR, SCName VARCHAR); // creating table

CREATE OR REPLACE PROCEDURE repo(DB VARCHAR,SC VARCHAR) 
    RETURNS string
    LANGUAGE JAVASCRIPT
    AS
    $$      
        var sql_command = `merge into TABL as t 
                            using (SELECT :1 as database,:2  as schema) as s 
                            on t.DBName = s.database 
                            and t.SCName = s.schema 
                            when matched then update 
                            set t.DBName = t.DBName 
                            when not matched then insert 
                            (DBName, SCName) VALUES (:1,:2)`;
        snowflake.execute({sqlText: sql_command, binds: [DB, SC]});

    return 'success';
    $$;
    
    call repo('a', 'b');

有关更多信息，请参见https://docs.snowflake.com/en/sql-reference/stored-procedures-usage.html#binding-variables。

使用雪花中的合并将存储过程的参数插入表中

1 个答案: