Question

我有一个d维数组， A ，矢量 inds ，长度等于d。我想在 inds 中访问 A 的值。

理想情况下，我会做类似 A（* inds）（借用Python的解包语法）。我不知道如何在MATLAB中做到这一点。

如果我 A（inds），我实际上会从 A 中获得单独的值，这不是我想要的。我想要的是 inds 的元素i是函数调用 A （）中的第i个参数。

Answer 1

一种解决方案是从您的下标索引inds向量中创建comma-separated list。您可以使用NUM2CELL将其转换为单元格数组，然后在编制{:}索引时使用A语法来执行此操作：

inds = num2cell(inds);
value = A(inds{:});

Answer 2

我认为这个工具可能对您有所帮助：

如果您有一个类似R = rand（5,10,15,20）的ND矩阵，并且您想要访问特定模式中的元素，则可以使用spindex以与输入访问相同的形状访问输出。所以如果你有大小（i1）= [5,5,5]，大小（i2）= [5,5,5]等等那么大小（spindex（R，i1，i2，i3，i4））也等于[5,5,5]。

%#example:

z = reshape(1:(5^4),[5,5,5,5]);
zid1 = [1,1,5];
zid2 = [1,2,5];
zid3 = [1,3,5];
zid4 = [1,4,5];
zOut = spindex(z,zid1,zid2,zid3,zid4)
%#   should be like [1,431,625]
zid1 = [1,2;3,4];
zid2 = [1,1;1,1];
zid3 = [1,1;1,1];
zid4 = [1,1;1,1];
zOut = spindex(z,zid1,zid2,zid3,zid4)
%%#    should be like [[1,2];[3,4]]

您需要将以下代码作为spindex.m添加到MATLAB路径中的某个位置。

 function outM = spindex(inM,varargin)
 %function outM = spindex(inM,varargin)
 %
 %returns a matrix indexed from inM via index variables contained in varargin
 %useful for retreiving multiple values from a large multidimensional matrix
 %
 %
 %inM is an N-d matrix
 %the index variables stored in varargin must be as numerous as the number of dimensions in inM
 %each index variable must be identical in size
 %
 %example:
 %
 %z = reshape(1:(5^4),[5,5,5,5]);
 %zid1 = [1,1,5];
 %zid2 = [1,2,5];
 %zid3 = [1,3,5];
 %zid4 = [1,4,5];
 %zOut = spindex(z,zid1,zid2,zid3,zid4)
 %%   should be like [1,431,625]
 %zid1 = [1,2;3,4];
 %zid2 = [1,1;1,1];
 %zid3 = [1,1;1,1];
 %zid4 = [1,1;1,1];
 %zOut = spindex(z,zid1,zid2,zid3,zid4)
 %%    should be like [[1,2];[3,4]]
 sz = size(inM);
 ndim = length(sz);
 if((ndim == 2) & (sz(2) ==1)) % ndim always returns at least 2
   ndim =1;
 end
 if(nargin ~= (ndim +1))
    extraDims = setdiff(1:(nargin - 1),1:ndim);
    for iExtraDim = extraDims
       if(any(varargin{iExtraDim}~=1))
          error('must have as many indicies as dimensions\n');
       end
    end
 end
 szid = size(varargin{1});
 for i = 1:ndim
    szid2 = size(varargin{i});
    if(any(szid2 ~= szid))
       error('indicies must have identical shape');
    end
    ndIdxs(:,i) = varargin{i}(:);
 end
 if(ndim == 1)
    idxs = ndIdxs(:,1);
 else
    idxs = myNDsub2ind(size(inM),ndIdxs);
 end
 outM = nan(1,length(idxs));
 outM(find(not(isnan(idxs)))) = inM(idxs(find(not(isnan(idxs)))));
 outM = reshape(outM,size(varargin{1}));





 function ndx = myNDsub2ind(siz,subs)
 %function ndx = NDsub2ind(siz,subs)
 %-------------------------------
 %works more smoothly when the dimensionality of the mtrx is unknown
 %siz should be like [10 10 4 5] if subs is like
 % 9 8 3 5
 % 1 1 1 1
 % 10 10 4 5
 % 5 8 3 3
 %
 % siz will be rotated for you if submit a row vec instead a col vector
 % example: NDsub2ind([10 10 4 5],[[9,8,3,5];[1,1,1,1]])
 %----------------------------------------------
 if(size(siz,1) > 1) && (size(siz,2) > 1)
    error('the siz variable must be a vector');
 end

 if((size(subs,1) ~= 1) && (size(subs,2) == 1))
    subs = subs';
 end
 siz = siz(:)';
 if length(siz)<2
         error('MATLAB:sub2ind:InvalidSize',...
             'Size vector must have at least 2 elements.');
 end

 if ((length(siz) ~= size(subs,2)))
     error('NDsub2ind: length(siz) must = size(subs,2)');
 end

 nPoints = size(subs,1);


 %Compute linear indices
 k = [1 cumprod(siz(1:end-1))];
 ndx = ones(nPoints,1);
 s = size(subs); %For size comparison
 for i = 1:length(siz),
     v = subs;
     fNaN = find(   (v(:,i) < 1) | (v(:,i) > siz(i))   );
     %Verify subscripts are within range
     v(fNaN,i) = nan;
     ndx = ndx + (v(:,i)-1)*k(i);
 end

MATLAB：使用列表访问多维数组的元素

2 个答案: