我在数据框(controids
)上具有一组位置的经度和纬度:
library(tidyverse)
centroids <-
tribble(
~city, ~long, ~lat,
"A", -89.92702, 44.19367,
"B", -89.92525, 44.19654,
"C", -89.92365, 44.19756,
"D", -89.91949, 44.19848,
"E", -89.91359, 44.19818)
我有第二个数据框(towns
),其中包含第二组位置的经度和纬度。
towns <-
tribble(
~town, ~long, ~lat,
"greentown", -89.92225, 44.19727,
"bluetown", -89.92997, 44.19899,
"redtown", -89.91500, 44.19600)
我想在centroids
中添加三列,以给出每个城市与towns
中三个城镇中每个城镇之间的直线距离(以公里为单位)。因此,最终数据帧将如下所示(距离不正确,仅用于说明):
output <-
tribble(
~city, ~long, ~lat, ~greentown_dist, ~bluetown_dist, ~redtown_dist,
"A", -89.92702, 44.19367, 5.3, 2.0, 1.2,
"B", -89.92525, 44.19654, 4.4, 2.3, 9.9,
"C", -89.92365, 44.19756, 3.7, 5.4, 3.3,
"D", -89.91949, 44.19848, 2.6, 3.9, 6.7,
"E", -89.91359, 44.19818, 10.2, 2.2, 3.1)
我必须在许多城镇中执行此操作,因此我试图编写一些易于推广的代码。这是我到目前为止所拥有的。
library(sf)
towns <- towns %>% st_as_sf(., coords=c('long', 'lat')) %>% st_geometry()
output <-
centroids %>%
st_as_sf(., coords=c('long', 'lat')) %>%
mutate(greentown_dist = st_distance(geometry, st_point(c( unlist(towns[1]) ))),
bluetown_dist = st_distance(geometry, st_point(c( unlist(towns[2]) ))),
redtown_dist = st_distance(geometry, st_point(c( unlist(towns[3]) ))))
我想知道是否有一种方法可以使用mutate_at
和/或purrr
map
函数-一种自动填写TOWN_dist列名并输入正确行的函数来自town
数据框。
答案 0 :(得分:1)
我们可以使用map
遍历“城镇”
centroids[paste0(c("green", "blue", "red"), "town_dist")] <- map(towns,
~ centroids %>%
st_as_sf(., coords = c('long', 'lat')) %>%
transmute(dist = st_distance(geometry, st_point(c( unlist(.x))))))