我制作了一个Android应用程序,它通过它循环访问XML Feed(并在网站上)并在Feed中显示图像。
我使用“图库”和“图片适配器”来显示所有图片 - 从网站加载图片(因为Feed提供了网址)
但是当电话改变时,应用程序会自行重置并且状态丢失 - 导致再次消耗馈送并重新加载图像(带宽非常大)
在ImageAdapter中,我创建了一个ImageView对象数组,允许我将从网站加载的图像保留在本地对象上(所以不要再加载它们)
但是,由于每次手机更改方向时都会重新设置应用程序,因此对象阵列会被删除,所有内容都会再次加载备份。
我正在尝试将此ImageView数组保存在App状态但无法找到正确的函数???
以下是代码:
package com.test;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import android.content.Context;
import android.graphics.drawable.Drawable;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.ImageView;
import android.widget.Toast;
public class ImageAdapter extends BaseAdapter {
private Context mContext;
private String[] mImageIds = {};
private String[] titles = {};
public ImageView[] images = {};
public ImageAdapter(Context c) {
mContext = c;
try{
//open local file and parse to XML
DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document doc;
doc = docBuilder.parse(mContext.openFileInput("xmlfeed.xml"));
doc.getDocumentElement().normalize();
NodeList itms = doc.getElementsByTagName("item");
String temp = "";
String tempTitles = "";
//loop through xml items to retreive all nodes
for (int i = 0; i < itms.getLength(); i++){
Node itm = itms.item(i);
if(temp==""){
temp = getTagValue(itm, "image");
tempTitles = getTagValue(itm, "title");
}else{
temp = temp + "," + getTagValue(itm, "image");
tempTitles = tempTitles + "," + getTagValue(itm, "title");
}
}
mImageIds = temp.split(",");
titles = tempTitles.split(",");
//create all images as empty vars
if(images.length==0){
images = new ImageView[itms.getLength()];
}
}
catch (Exception e) {
e.printStackTrace();
}
}
public int getCount() {
return mImageIds.length;
}
public Object getItem(int position) {
return position;
}
public long getItemId(int position) {
return position;
}
public View getView(int position, View convertView, ViewGroup parent) {
//loads the image in case it does not already exists in the object
if(images[position]==null){
ImageView imgs = new ImageView(mContext);
try{
imgs.setImageDrawable(drawable_from_url(mImageIds[position], "src"));
}catch(Exception e){
e.printStackTrace();
}
imgs.setScaleType(ImageView.ScaleType.FIT_XY);
images[position] = imgs;
}
return images[position];
}
Drawable drawable_from_url(String url, String src_name) throws java.net.MalformedURLException, java.io.IOException{
Toast.makeText(mContext, url, Toast.LENGTH_SHORT).show();
return Drawable.createFromStream(((java.io.InputStream)new java.net.URL(url).getContent()), src_name);
}
public String getTagValue(Node itm, String tagName){
String title_value = "";
if (itm.getNodeType() == Node.ELEMENT_NODE)
{
Element itmElm = (Element) itm;
NodeList title = itmElm.getElementsByTagName(tagName);
Element titleElm = (Element) title.item(0);
NodeList title_nodes = titleElm.getChildNodes();
title_value = ((Node) title_nodes.item(0)).getNodeValue().trim();
}
return title_value;
}
}
请帮助,我将如何在应用程序状态中保存?
答案 0 :(得分:0)
这是因为你的listview是在Activity A的oncreate()方法中定义的。 执行以下活动以使UIfreeze处于屏幕方向
将以下内容添加到清单中的活动声明:
android:configChanges="orientation"
所以它看起来像
<activity android:label="@string/app_name"
android:configChanges="orientation|keyboardHidden"
android:name=".your.package">
问题是,当配置发生变化时,系统会破坏活动。
由于 迪帕克