使用CTE进行字符串拆分的有效方法

时间:2011-06-17 05:10:27

标签: sql sql-server sql-server-2005 tsql common-table-expression

我有一张类似

的表格
ID  Layout
1   hello,world,welcome,to,tsql
2   welcome,to,stackoverflow

所需的输出应为

Id  Splitdata
1   hello
1   world
1   welcome
1   to
1   tsql
2   welcome
2   to
2   stackoverflow

我通过以下查询

完成了这项工作
Declare @t TABLE(
    ID  INT IDENTITY PRIMARY KEY,
    Layout VARCHAR(MAX)
)
INSERT INTO @t(Layout)
SELECT 'hello,world,welcome,to,tsql' union all
SELECT 'welcome,to,stackoverflow'
--SELECT * FROM @t
;With cte AS(
select F1.id
 ,O.splitdata 
 from
 (
 select *,
 cast('<X>'+replace(F.Layout,',','</X><X>')+'</X>' as XML) as xmlfilter
 from @t F
 )F1
 cross apply
 ( 
 select fdata.D.value('.','varchar(MAX)') as splitdata 
 from f1.xmlfilter.nodes('X') as fdata(D)) O
 )

 select * from cte

但表现明智,这是非常糟糕的。我正在寻找一个更有效的查询,但只使用CTE。

请帮忙

由于

3 个答案:

答案 0 :(得分:11)

你似乎已经开始使用CTE了,所以试试这个:

DECLARE @YourTable table (RowID int, Layout varchar(200))
INSERT @YourTable VALUES (1,'hello,world,welcome,to,tsql')
INSERT @YourTable VALUES (2,'welcome,to,stackoverflow')

;WITH SplitSting AS
(
    SELECT
        RowID,LEFT(Layout,CHARINDEX(',',Layout)-1) AS Part
            ,RIGHT(Layout,LEN(Layout)-CHARINDEX(',',Layout)) AS Remainder
        FROM @YourTable
        WHERE Layout IS NOT NULL AND CHARINDEX(',',Layout)>0
    UNION ALL
    SELECT
        RowID,LEFT(Remainder,CHARINDEX(',',Remainder)-1)
            ,RIGHT(Remainder,LEN(Remainder)-CHARINDEX(',',Remainder))
        FROM SplitSting
        WHERE Remainder IS NOT NULL AND CHARINDEX(',',Remainder)>0
    UNION ALL
    SELECT
        RowID,Remainder,null
        FROM SplitSting
        WHERE Remainder IS NOT NULL AND CHARINDEX(',',Remainder)=0
)
SELECT * FROM SplitSting ORDER BY RowID

输出:

RowID       Part                   
----------- -----------------------
1           hello                  
1           world                  
1           welcome                
1           to                     
1           tsql                   
2           welcome                
2           to                     
2           stackoverflow          

(8 row(s) affected)

这是一篇关于在SQL Server中分割字符串的优秀文章:"Arrays and Lists in SQL Server 2005 and Beyond, When Table Value Parameters Do Not Cut it" by Erland Sommarskog

编辑这是另一个版本(但你需要一个数字表)返回与上面相同的结果:

;WITH SplitValues AS
(
    SELECT
        RowID,ListValue
        FROM (SELECT
                  RowID, LTRIM(RTRIM(SUBSTRING(List2, number+1, CHARINDEX(',', List2, number+1)-number - 1))) AS ListValue
                  FROM (
                           SELECT RowID, ',' + Layout + ',' AS List2
                           FROM @YourTable
                       ) AS dt
                      INNER JOIN Numbers n ON n.Number < LEN(dt.List2)
                  WHERE SUBSTRING(List2, number, 1) = ','
             ) dt2
        WHERE ListValue IS NOT NULL AND ListValue!=''
)
SELECT * FROM SplitValues

请点击此处查看数字表:What is the best way to create and populate a numbers table?

答案 1 :(得分:3)

这是我使用CTE的最佳解决方案:

DECLARE @Char VARCHAR(MAX) = '10||3112||||aaaa||'
DECLARE @Separador CHAR(2) = '||'

;WITH Entrada AS(
    SELECT
        CAST(1 AS Int) As Inicio,
        CHARINDEX(@Separador, @Char) As Fim
    UNION ALL
    SELECT
        CAST(Fim + LEN(@Separador) AS Int) As Inicio,
        CHARINDEX(@Separador, @Char, Fim + 1) As Fim
    FROM Entrada
    WHERE CHARINDEX(@Separador, @Char, Fim + 1) > 0
)
SELECT 
    SUBSTRING(@Char, Inicio, Fim - Inicio)
FROM Entrada
WHERE (Fim - Inicio) > 0

答案 2 :(得分:0)

来自NullRef的答案

根据我对sql server

的理解,没有设置操作的功能会更快

所以这将是非常有效的

CREATE FUNCTION fnSplitString(@str nvarchar(max),@sep nvarchar(max))
RETURNS TABLE
AS
RETURN
    WITH a AS(
        SELECT CAST(0 AS BIGINT) as idx1,CHARINDEX(@sep,@str) idx2
        UNION ALL
        SELECT idx2+1,CHARINDEX(@sep,@str,idx2+1)
        FROM a
        WHERE idx2>0
    )
    SELECT SUBSTRING(@str,idx1,COALESCE(NULLIF(idx2,0),LEN(@str)+1)-idx1) as value
    FROM a