使用JSDoc从返回值推断类型

Question

从函数返回类型分配类型的正确方法是什么？

class Vector2 {
private:
    float x, y;
public:
    Vector2(float _x, float _y) {
        x = _x;
        y = _y;
    }

    // Dot product
    float operator*(const Vector2& other) {
        return x * other.x + y * other.y;
    }

    // Magnitude (abs)
    float Magnitude() {
        float dot = (this) * (this); // HERE IS THE ERROR: expression must have arithmetic or unscoped enum type
        return std::sqrt(dot);
    }

    Vector2 operator+(const Vector2& other) {
        return Vector2(x + other.x, y + other.y);
    }
};

如VSCode所示，返回类型可用。我只是不知道如何在不调用函数的情况下获取它。

Answer 1

可能不符合 JSDoc 规范，但 VS Code 支持 JSDoc 中的 Typescript 语法。

SELECT *
FROM (SELECT Name, Price, AVG(Price) OVER (PARTITION BY Name) AS Average_Price
      FROM items) AS X
WHERE X.Price > X.Average_Price

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