Question

我正在尝试使用findByIdAndUpdate在猫鼬中更新“ Board”模型，并且该模型在模型上具有一个“ items”（即对象）数组。我可能不太了解猫鼬，但由于某种原因，数组中的每个项目都会随董事会一起生成一个ID。这不是问题，实际上很方便，但是，在执行findByIdAndUpdate之后，每个项目的ID都已更改。这让我感到非常惊讶，我真的以为他们会保持不变。这可能是由于更新数组中的所有项目引起的吗？猫鼬也许只是扔掉整个数组并在更新时创建一个新数组（也许有人知道吗？）。无论如何，我的问题是：有没有一种方法可以在不更改这些ID的情况下更新模型。我真的希望他们保持一致。我用于更新的代码是

exports.updateBoard = asyncHandler(async (req, res, next) => {

  let board = await Board.findById(req.params.id);

  if (!board) {
    return next(new CustomError(`Board not found with id of ${req.params.id}`, 404));
  }

  // Authorize user
  if (board.user.toString() !== req.user.id) {
    return next(new CustomError(`User ${req.user.id} is not authorized to update board ${board._id}`, 401));
  }

  req.body.lastUpdated = Date.now();

  board = await Board.findByIdAndUpdate(req.params.id, req.body, { new: true, runValidators: true })
                              .select('-__v')
                              .populate({
                                path: 'user',
                                select: 'name avatar',
                              });

  // 200 - success
  res.status(200).json({ success: true, data: board });

});

和BoardSchema：

const BoardSchema = new Schema(
  {
    user: {
      type: Schema.Types.ObjectId,
      ref: 'User',
      required: [true, 'Board must have a user'],
    },
    name: {
      type: String,
      required: true,
      trim: true,
    },
    description: {
      type: String,
      required: false,
      trim: true,
    },
    items: [
      {
        title: {
          type: String,
          required: true,
          trim: true,
        },
        description: {
          type: String,
          required: false,
          trim: true,
        },
        dateCreated: {
          type: Date,
          default: Date.now,
        },
        lastUpdated: {
          type: Date,
          default: Date.now,
        },
      },
    ],
    columns: [
      {
        name: {
          type: String,
          required: true,
        },
        index: {
          type: Number,
          required: true,
        },
        show: {
          type: Boolean,
          required: true,
        },
      },
    ],
    dateCreated: {
      type: Date,
      default: Date.now,
    },
    lastUpdated: {
      type: Date,
      default: Date.now,
    },
  },
  {
    toJSON: { virtuals: true },
    toObject: { virtuals: true },
  },
);

如何在猫鼬的findByIdAndUpdate上保留ID

0 个答案: