提供者:查找停用的小部件的祖先是不安全的

时间:2020-09-08 11:57:52

标签: flutter dart provider

尝试从提供程序获取值,效果很好,但出现以下错误。我在这里做错了什么?

  @override
  Widget build(BuildContext context) {
    String route = Provider.of<User>(context) == null ? Router.LOGIN : Router.HOME;
    Future.delayed(const Duration(seconds: 2), () => Navigator.pushReplacementNamed(context, route));

    return Scaffold(........

错误

E/flutter (23058): [ERROR:flutter/shell/common/shell.cc(209)] Dart Error: Unhandled exception:
E/flutter (23058): Looking up a deactivated widget's ancestor is unsafe.
E/flutter (23058): At this point the state of the widget's element tree is no longer stable.
E/flutter (23058): To safely refer to a widget's ancestor in its dispose() method, save a reference to the ancestor by calling dependOnInheritedWidgetOfExactType() in the widget's didChangeDependencies() method.

1 个答案:

答案 0 :(得分:0)

问题是无法等待导航器调用。如果您需要导航到正确的构建页面,则创建一个没有返回类型的异步方法,然后在initState中调用该方法。

_checkUserExistsAndNavigate() async {
  String route = Provider.of<User>(context) == null ? Router.login : Router.home;
await Future.delayed(seconds: 2), () => Navigator.pushReplacementNamed(context, route);
}

@initState(() {
_checkUserExistsAndNavigate();
super.initState();
}