Pytube3仅下载前100个视频

Question

我目前正在尝试使用pytube3库构建自己的youtube视频/播放列表下载器

我观察到pytube3只允许我下载播放列表中的前100个视频'

有没有解决的办法，所以我可以下载100多个视频？

https://github.com/jlearnph/YouTube-Downloader/blob/master/youtube_downloader.py

from pytube import Playlist
from pytube import YouTube
import re
import PySimpleGUI as sg

# sg.theme('DarkAmber')  #theme

layout = [[sg.Text('Enter video / playlist link: ')],      
          [sg.Input(key='link')],
          [sg.Text('Download Folder: '), sg.In(size=(25,1), enable_events=True ,key='-FOLDER-'), sg.FolderBrowse()],
          [sg.Button('Download'), sg.Exit()],
          [sg.Text('Downloading:'), sg.Text(size=(15,1), key='-OUTPUT-')]
          ]      

window = sg.Window('YouTube Downloader by JLearn PH', layout)      

while True:                         
    event, values = window.read()
    link = values['link']
    show = ''
    download_folder = values['-FOLDER-']

    #for a playlist
    if event == 'Download':
        if (link == '' and download_folder == ''):
            sg.popup_error('Enter a YouTube Link and Download Folder')
        elif link == '':
            sg.popup_error('Enter a YouTube Link')
        elif download_folder == '':
            sg.popup_error('Select Download Folder')
        else:
            try:
                playlist = Playlist(link)
                playlist._video_regex = re.compile(r"\"url\":\"(/watch\?v=[\w-]*)")
                show += f'\nStarting download for {len(playlist.video_urls)} videos\n'
                count = 1
                for url in playlist.video_urls:
                    try:
                        yt = YouTube(url)
                        yt.streams.first().download(download_folder)
                        show += f'\n[+] Success {count}: {yt.title}'
                    except:
                        show += f'\n[+] Failed {count}: {yt.title}'
                    count +=1
                    window['-OUTPUT-'].update(f'{count-1}/{len(playlist.video_urls)}')

            #for only 1 video
            except:
                show += '\nStarting download for 1 video\n'
                show += f'\n[+] Video: {link}'
                YouTube(link).streams.first().download(download_folder)
            
            sg.popup_scrolled(f'{show}\n\nFinished Downloading\n', size=(100,20))
        

    if (event == sg.WIN_CLOSED or event == 'Exit'):
        break      


window.close()

谢谢