Question

以下示例中的我的问题。我几乎在那里建立了一个新的对象数组并重命名了一些属性。但是那里只显示国家。其他属性是“未定义”。

我试图做这样的事情：name: t.cities[0].id,

但是此方法并未遍历以下对象，仅遍历第一个

预先感谢

let data = [
  {
      "country": "italy",
      "cities": [
          {
              "id": "milan",
              "count": "1366180",              
          },
          {
              "id": "rome",
              "count": "2870500",   
          },
          {
              "id": "torino",
              "count": "870952",   
          }   
      ]
  },
  {
      "country": "france",
      "cities": [
          {
              "id": "paris",
              "count": "2148327",              
          },
          {
              "id": "marseille",
              "count": "869815",   
          },
          {
              "id": "lyon",
              "count": "516092",   
          }   
      ]
  }
]

let rename = data.map( a => ({
  country: a.country,
  cities: data.map( t => ({          
    name: t.cities.id,
    population: t.cities.count,          
  }))
}));

console.log( rename )

Answer 1

内部data.map()应该是a.cities.map()。并且此地图接收单个城市对象，您可以直接访问id和count属性，它们不需要是嵌套属性。

let data = [
  {
      "country": "italy",
      "cities": [
          {
              "id": "milan",
              "count": "1366180",              
          },
          {
              "id": "rome",
              "count": "2870500",   
          },
          {
              "id": "torino",
              "count": "870952",   
          }   
      ]
  },
  {
      "country": "france",
      "cities": [
          {
              "id": "paris",
              "count": "2148327",              
          },
          {
              "id": "marseille",
              "count": "869815",   
          },
          {
              "id": "lyon",
              "count": "516092",   
          }   
      ]
  }
]

let rename = data.map( a => ({
  country: a.country,
  cities: a.cities.map( city => ({          
    name: city.id,
    population: city.count,          
  }))
}));

console.log( rename )

如何获得物体的财产价值？

1 个答案: