Deno post方法为空的请求正文

时间:2020-09-03 16:54:39

标签: json api rest deno insomnia

我目前正在使用 Deno 开发概念验证的REST api应用,而我的 post方法遇到了问题(getAll等了)。我的请求的正文不包含因失眠而发送的数据

我的方法:

addQuote: async ({ request, response }: { request: any; response: any }) => {
    const body = await request.body();
    if (!request.hasBody) {
      response.status = 400;
      response.body = { message: "No data provided" };
      return;
    }

    let newQuote: Quote = {
      id: v4.generate(),
      philosophy: body.value.philosophy,
      author: body.value.author,
      quote: body.value.quote,
    };

    quotes.push(newQuote);
    response.body = newQuote;
  },

请求:

insomnia json request

响应:

insomnia json response

我将Content-Type - application/json放在标题中。
如果我只返回body.value,则为空。

感谢帮助!

1 个答案:

答案 0 :(得分:3)

由于值类型是可以保证的,我们必须在访问值之前先进行解析。

尝试一下:

addQuote: async ({ request, response }: { request: any; response: any }) => {
    const body = await request.body(); //Returns { type: "json", value: Promise { <pending> } }
    if (!request.hasBody) {
      response.status = 400;
      response.body = { message: "No data provided" };
      return;
    }
    const values = await body.value;
    let newQuote: Quote = {
      id: v4.generate(),
      philosophy: values.philosophy,
      author: values.author,
      quote: values.quote,
    };

    quotes.push(newQuote);
    response.body = newQuote;
  }