Question

我试图创建一个正则表达式来清理Amazon URL，但是我无法删除中间部分。

在所附示例中，我希望“组2”在最终结果中消失。有可能吗？

我使用以下正则表达式：^(?:http:\/\/|www\.|https:\/\/)([^\/]+)(\s?.*)(/[dg]p/)([^/]+)

我将得到这样的结果：

https://www.amazon.com/adidas-Melange-Performance-T-Shirt-Charcoal/dp/B07P4LVZNL/ref=sr_1_fkmr1_2?dchild=1&keywords=Adidas+M%C3%A8lange+Tech+T-Shirt+A372&qid=1579685244&sr=8-2-fkmr1 --> https://www.amazon.com/dp/B07P4LVZNL

https://www.amazon.com/adidas-Originals-Solid-Melange-Purple/dp/B07DXPN7TK/ref=sr_1_fkmr2_1?dchild=1&keywords=Adidas+M%C3%A8lange+Tech+T-Shirt+A372&qid=1579685244&sr=8-1-fkmr2 --> https://www.amazon.com/dp/B07DXPN7TK

https://www.amazon.es/gp/B07R23QGH6/ref=sr_1_fkmr2_2?dchild=1&keywords=Adidas+M%C3%A8lange+Tech+T-Shirt+A372&qid=1579685244&sr=8-2-fkmr2 --> https://www.amazon.com/gp/B07R23QGH6

https://www.amazon.it/dp/B07R23QGH6/ --> https://www.amazon.it/dp/B07R23QGH6/

https://regex101.com/r/AFGk96/1

Answer 1

您在逃避。在正则表达式中，斜杠没有任何意义，不需要将其转义：

^(?:http:\/\/|www\.|https:\/\/)([^\/]+)(\s?.*)(/[dg]p/)([^/]+)

可能（还有一些其他简化）

^(?:https?://)?(www[^/]+).*?(/[dg]p/[^/]+)

当我们在末尾添加.*以匹配字符串的尾部时，我们得到的结果是有效的：

import re

amazon_url_pattern = re.compile(r'^(?:https?://)?(www[^/]+).*?(/[dg]p/[^/]+).*')

url = 'https://www.amazon.com/adidas-Melange-Performance-T-Shirt-Charcoal/dp/B07P4LVZNL/ref=sr_1_fkmr1_2?dchild=1&keywords=Adidas+M%C3%A8lange+Tech+T-Shirt+A372&qid=1579685244&sr=8-2-fkmr1'
result = amazon_url_pattern.sub(r'\1\2/', url)

print(result)

打印

https://www.amazon.com/dp/B07P4LVZNL/

正则表达式以清理Amazon链接

1 个答案: