Question

编辑：我想加入以下查询

QUERY1

SELECT     r.userId, r.programmeId, u.email, u.firstName, u.lastName, u.profileId, tblProgrammes.name, u.storeId, r.dateEnded AS lastPass, r.dateExpired
FROM         tblUserRepeatHistory AS r INNER JOIN
                      tblUsers AS u ON r.userId = u.id INNER JOIN
                      tblProgrammes ON r.programmeId = tblProgrammes.id
WHERE     (u.storeId = @storeId) AND (r.userId = @userId)
GROUP BY r.userId, r.programmeId, u.email, u.firstName, u.lastName, u.profileId, tblProgrammes.name, u.storeId, r.dateEnded, r.dateExpired
HAVING      (DATEDIFF(D, MAX(r.dateExpired), GETDATE() + 31) >= 0)

使用

QUERY2

SELECT TOP (1) r.id, p.maxSteps
FROM tblUserQuestionnaireHistory AS r INNER JOIN
tblProgrammes AS p ON r.programmeId = p.id AND r.stepId = p.maxSteps
WHERE (r.userId = @UserId) AND (r.programmeId = @ProgrammeId) AND (r.success = 1)
ORDER BY r.id DESC

语法应如下

从QUERY1中选择全部与QUERY2联合WHERE QUERY2不记录任何记录。即如果QUERY2返回true，则从不介意从第一部分返回记录

从QUERY1中选择* WHERE NOT EXISTS JOIN QUERY2其中查询2中的@userId和@programmeId来自QUery1

Answer 1

您可以使用outer apply查找符合条件的top 1行：

select  *
from    tblUserRepeatHistory u
outer apply
        (
        select  top 1 *
        from    tblUserQuestionnaireHistory r
        on      r.userId = u.UserId
                and r.programmeId = u.programmeId
                and r.success = 1
                and r.stepId = 9
        ) as r

Answer 2

这是你的意思吗？

SELECT r.userId, r.programmeId, u.email, u.firstName, (SELECT TOP (1) r.id FROM tblUserQuestionnaireHistory AS r WHERE (r.userId = urh.UserId) AND (r.programmeId = urh.ProgrammeId) AND (r.success = 1) AND r.stepId = 9)
FROM tblUserRepeatHistory urh
where urh.UserId = @UserId and usr.ProgrammeId = @programmeId

SQL选择具有2个部分的查询逻辑

2 个答案: