无法点击弹出窗口并关闭

Question

我已打开此网站https://www.seleniumeasy.com/test/basic-first-form-demo.html

打开时，弹出窗口显示

如何使用硒继续弹出窗口并单击关闭？

Answer 1

使用以下代码。这些是您没有使用适当的等待和XPath的机会。

System.setProperty("webdriver.chrome.driver", System.getProperty("user.dir") + "\\src\\test\\resources\\executables\\chromedriver.exe");
    WebDriver driver = new ChromeDriver();
    driver.get("https://www.seleniumeasy.com/test/basic-first-form-demo.html");
    WebDriverWait wait = new WebDriverWait(driver, 20);
    wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//*[@id='at-cv-lightbox-close']")));
    driver.findElement(By.xpath("//*[@id='at-cv-lightbox-close']"));
    driver.quit();

Answer 2

要单击并关闭弹出窗口，您需要为elementToBeClickable()引入WebDriverWait，并且可以使用以下任一Locator Strategies：

• cssSelector：

  new WebDriverWait(webDriver, 20).until(ExpectedConditions.elementToBeClickable(By.cssSelector("a[title='Close']"))).click();
  

• xpath：

  new WebDriverWait(webDriver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//a[@title='Close']"))).click();