Question

我查看了多个相似的实例（如下所述），它们的错误几乎相同，但是我发现我的情况有些不同。有人可以帮我吗？

在我的情况下，确切的异常消息是-

Could not commit JPA transaction; nested exception is javax.persistence.RollbackException: Error while committing the transaction

当我尝试保存与MarriagePerson关系的@ManyToOne实体时，会发生此问题 User。请在下面找到实体及其关系-

User.java

@Entity
@Table(name = "MAIN_USER")
public class User {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @OneToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL, mappedBy = "user")
    private Collection<MarriagePerson> marriagePerson = new ArrayList<MarriagePerson>();

    @NotEmpty(message = "Name can not be empty")
    @Size(min = 2, max = 20, message = "Name must be between 2 and 20 characters long")
    @Column(name = "first_name")
    private String firstName;

    @Column(name = "middle_name")
    private String middleName;

    @Column(name = "last_name")
    private String lastName;

    @NotEmpty(message = "Email can not be empty")
    @Size(min = 5, message = "Email must be more than 5 characters long")
    @Column(name = "email", unique = true)
    private String email;

    @Column(name = "alternateEmail")
    private String alternateEmail;

    @NotEmpty(message = "Mobile can not be empty")
    @Size(min = 10, max = 10, message = "Mobile must be 10 digits long")
    @Column(name = "mobile", unique = true)
    private String mobile;

    @Column(name = "alternate_mobile")
    private String alternateMobile;

    @NotEmpty(message = "Password can not be empty")
    @Size(min = 6, message = "Password must be more than 6 characters long")
    @Column(name = "password")
    private String password;
}

MarriagePerson.java

@Entity
@Table(name = "MARRIAGE_PERSON")
public class MarriagePerson {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long id;

    @ManyToOne
    @JoinColumn(columnDefinition = "user_id")
    private User user;

    @NotEmpty
    @Column(name = "gender")
    private String gender;

    @NotEmpty(message = "Name can not be empty")
    @Size(min = 2, max = 20, message = "Name must be between 2 and 20 characters long")
    @Column(name = "firstName")
    private String firstName;
}

这正是我在做什么-

我在User数据库中保存了一个postgres。
现在，我尝试将MarriagePerson保存为相同的User，然后捕获到上述异常。

请在下面找到UserSerive和MarriagePersonService-

UserService.java

@Service
public class UserService implements IUserService {

    @Autowired
    private IUserRepository userRepository;
    
    @Override
    public User save(User user) {
        return userRepository.save(user);
    }
}

MarriagePerson.java

@Service
public class MarriagePersonService implements IMarriagePersonService {

    @Autowired
    private IMarriagePersonRepository marriagePersonRepository;

    @Override
    public MarriagePerson save(MarriagePerson marriagePerson) {
        userRepository.findById(userId).map(user -> {
            marriagePerson.setUser(user);
            return marriagePersonRepository.save(marriagePerson);
        });
        return marriagePerson;
    }
}

在此行marriagePersonRepository.save(marriagePerson);处捕获了以下提到的请求有效负载的异常-

MarriagePerson有效载荷

{
  "firstName": "Name",
  "gender": "Male"
}

已保存的用户数据在下面（我们正在尝试为此更新MarriagePerson）

{
    "firstName": "string",
    "middleName": "string",
    "lastName": "string",
    "email": "string@string.com",
    "alternateEmail": "string1@string.com",
    "mobile": "0123456789",
    "alternateMobile": "0123456789",
    "password": "string",
    "marriagePerson": []
}

编辑

存储库接口为-

IMarriagePersonRepository.java

@Repository
public interface IMarriagePersonRepository
        extends JpaRepository<MarriagePerson, Long>, JpaSpecificationExecutor<MarriagePerson> {
    List<MarriagePerson> findAll();
}

IUserRepository.java

@Repository
public interface IUserRepository extends JpaRepository<User, Long> {
    public User findByMobile(String mobile);
    User findByMobileAndEmail(String mobile, String email);
}

谢谢。

无法提交JPA事务：嵌套异常为javax.persistence.RollbackException：提交事务时出错

0 个答案: