Question

我目前正在尝试使用python（对我来说几乎是全新的东西）在Discord中创建一个机器人。我试图做一个AFK函数（类似于Dyno的函数）。这是我的代码：

afkdict = {}
@client.command(name = "afk", brief = "Away From Keyboard",
                description = "I'll give you the afk status and if someone pings you before you come back, I'll tell "
                              "them that you are not available. You can add your own afk message!")
async def afk(ctx, message = "They didn't leave a message!"):
    global afkdict

    if ctx.message.author in afkdict:
        afkdict.pop(ctx.message.author)
        await ctx.send('Welcome back! You are no longer afk.')

    else:
        afkdict[ctx.message.author] = message
        await ctx.send("You are now afk. Beware of the real world!")


@client.event
async def on_message(message):
    global afkdict

    for member in message.mentions:  
        if member != message.author:  
            if member in afkdict:  
                afkmsg = afkdict[member]  
                await message.channel.send(f"Oh noes! {member} is afk. {afkmsg}")
    await client.process_commands(message)

我的问题是，使用此功能的用户将成为AFK，直到他们再次写入>afk。我的意图是使无论用户是否使用漫游器功能，只要用户在服务器中再次交谈，该漫游器就能够删除AFK状态。我知道这是有可能的，因为其他机器人也这样做了，但是我迷失了方向，无法想办法。预先感谢！

Answer 1

async def on_message(message):
    global afkdict
    if message.author in afkdict:
       afkdict.pop(message.author)

    for member in message.mentions:  
        if member != message.author:  
            if member in afkdict:  
                afkmsg = afkdict[member]  
                await message.channel.send(f"Oh noes! {member} is afk. {afkmsg}")
    await client.process_commands(message)

我认为应该这样做，但是您也可以再次传递ctx或将ctx保存为要访问的参数。但是此版本不会通知用户，他们不再是afk

Discord Bot中的AFK功能

1 个答案: