Question

我想使用GGPLOT2使用两个Y轴为两个类别的箱形图提供不同信息。如下图所示：

对于区域（AM和AR），我有两个类别信息（速度和旋转角度），我想将这两种运动方式组合到根据区域进行分组的图形中。

到目前为止，我的代码如下：

areaveleang <- ggplot(dados2, aes(x = area)) +
        geom_boxplot(aes(y = speed, color="Bruto" ), fill = "darkblue", alpha=0.7) +
  geom_boxplot(aes(y = angulo_modulo), color="#a50026", position = "dodge") +
        scale_y_continuous(name = "speed (km/h)", sec.axis = sec_axis(~ . *6,name=expression("turn angle (graus)"))) +
                           #breaks = seq(0, 175, 25),
                           #limits=c(0, 175)) +
        scale_x_discrete(name = "Area") +
        #ggtitle("Boxplot of mean ozone by month") +
        theme_bw() +
        theme(plot.title = element_text(size = 14, family = "Tahoma", face = "bold"),
              text = element_text(size = 12, family = "Tahoma"),
              axis.title = element_text(face="bold"),
              axis.text.x=element_text(size = 11),
              legend.position = "bottom") +
        scale_fill_brewer(palette = "Accent")

部分数据：

structure(list(lon = c(-38.8745, -38.8676, -38.9445, -38.9811, 
-38.9322, -38.9386), lat = c(-14.09437, -14.25664, -14.34518, 
-14.51857, -14.95994, -15.41684), bmode = c(1.396, 1.375, 1.346, 
1.248, 1.074, 1.289), bmode.5 = c(1, 1, 1, 1, 1, 1), ID = structure(c(53L, 
53L, 53L, 53L, 53L, 53L), .Label = c("10946.05", "20162.03", 
"21792.03", "21800.03", "21810.03", "24640.03", "24641.05", "24642.03", 
"27258.05", "27259.03", "27261.03", "27261.05", "27261.07", "33000.05", 
"37231.07", "37234.05", "37288.07", "42521.07", "50682.07", "50687.07", 
"60004.07", "81122.09", "81123.09", "81124.09", "81125.09", "81126.09", 
"84497.1", "87632.12", "87759.08", "87761.08", "87762.08", "87763.08", 
"87764.08", "87765.08", "87766.08", "87768.08", "87768.11", "87769.11", 
"87770.08", "87773.08", "87773.1", "87773.11", "87774.09", "87774.11", 
"87775.08", "87776.08", "87776.11", "87777.1", "87778.08", "87783.09", 
"88724.1", "88727.09", "111868.11", "111871.12", "112702.12", 
"112712.12", "112714.12", "120947.12", "121189.12", "121192.12", 
"121196.12", "1211931.12"), class = "factor"), sex = structure(c(3L, 
3L, 3L, 3L, 3L, 3L), .Label = c("F", "Fc", "M"), class = "factor"), 
    speed = c(0.921691675, 2.990097297, 2.137609076, 3.259383146, 
    8.173674567, 8.413534172), area = structure(c(3L, 3L, 3L, 
    3L, 3L, 3L), .Label = c("AA", "AM", "AR"), class = "factor"), 
    angulo = c(41.027, -43.41, 29.056, 18.241, -7.125, -4.702
    ), angle_rel = c(0.7160619, -0.7576522, 0.5071251, 0.3183724, 
    -0.1243479, -0.08206201), bat.depth = c(-45L, -397L, -32L, 
    -29L, -21L, -3L), dist = c(5.53015005, 17.94058378, 12.82565446, 
    19.55629887, 49.0420474, 50.48120503), angulo_modulo = c(41.027, 
    43.41, 29.056, 18.241, 7.125, 4.702), curva = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L), .Label = c("curva", "reta"), class = "factor")), row.names = 2:7, class = "data.frame")

PS：对不起，我的英语不好，我希望你能理解我的问题xD

Answer 1

不确定我是否正确，但是也许这正是您想要的：

要正确设置辅助轴的比例，您必须对数据应用逆变换，即，乘以6时，必须将数据中的struct Login: View { @Binding var isLoggedIn: Bool var myLogin: myLoginClass = myLoginClass() var body: some View { Button(action: { self.myLogin.loginWithCompletion { isSucceeded in if isSucceeded { self.isLoggedIn.toggle() } } }) { Text("Log me in") } } } class myLoginClass { // Completing method // Here would be your code that would "complete" true if successfully logged in or false if error // I'm just waiting to "simulate" the visual process func loginWithCompletion(completion: @escaping (Bool) -> Void) { DispatchQueue.main.asyncAfter(deadline: .now() + 2) { completion(true) } } }除以6。
要躲避两个箱形图，我建议使用angulo_modulo，以便您的两个变量成为一个变量的两个类别，默认情况下名为tidyr::pivot_longer，而值进入{{ 1}}。这样，您可以将name上的value和value，y和name上的color映射。默认情况下，alpha将为您提供每个区域两个并排的箱形图。

fill

带两个Y轴的分组箱线图

1 个答案: