如何从熊猫系列中删除拖尾点？

Question

如何从熊猫系列中删除尾随点？

我的尝试

import numpy as np
import pandas as pd

pd.set_option('max_colwidth',1000)

s = pd.Series(["""Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperias… http://instagram.com/p/YGEt5JC6JM/"""])


s.str.replace(r'(\w)\.+',r'\1',regex=True)

我的结果

Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperias… http://instagramcom/p/YGEt5JC6JM/


wanted:
Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperia http://instagramcom/p/YGEt5JC6JM/

Answer 1

这些不是句点，而是省略号字符，它是Unicode字符\u2026。参见How should I write three dots?

s.str.replace(r'(\w)\u2026+',r'\1',regex=True)

Answer 2

您可以尝试按照显示的示例编写吗？

pd.set_option('max_colwidth',1000)
s = pd.Series(["""Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperias… http://instagram.com/p/YGEt5JC6JM/"""])
s.str.replace(r'…+',r'')

Answer 3

根据Barmar的建议：

s = pd.Series(["""Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperias… http://instagram.com/p/YGEt5JC6JM/"""])


s.str.replace(r'(\w)…',r'\1',regex=True)

Gives:
Finally a transparant silicon case ^^ Thanks to my uncle :) #yay #Sony #Xperia #S #sonyexperias http://instagram.com/p/YGEt5JC6JM/