Question

所以我的代码由2部分和测试这3部分组成。想法是2类使用测试输入来形成矩形。这是测试代码

@Test
    public void testRectangle1() {
        Point center = new Point(20, 30);
        Rectangle rect = new Rectangle(center, 20, 20);
        assertAll(
                () -> assertEquals(10, rect.getTopLeft().getX()),
                () -> assertEquals(20, rect.getTopLeft().getY()),
                () -> assertEquals(30, rect.getBottomRight().getX()),
                () -> assertEquals(40, rect.getBottomRight().getY()),
                () -> assertEquals(20, rect.getWidth()),
                () -> assertEquals(20, rect.getHeight())
        );
    }

名为Point的第一类工作正常。

public class Point {

    private int x, y;

    public Point(int x, int y) {
        this.x = x;
        this.y = y;
    }

    public Point() {
        this(0, 0);
    }

    public int getX() {
        return x;
    }

    public void setX(int x) {
        this.x = x;
    }

    public int getY() {
        return y;
    }

    public void setY(int y) {
        this.y = y;
    }

    public void moveTo(int newX, int newY) {
        x = newX;
        y = newY;
    }

    public void moveRel(int dx, int dy) {
        x += dx;
        y += dy;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + x;
        result = prime * result + y;
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        Point other = (Point) obj;
        if (x != other.x)
            return false;
        if (y != other.y)
            return false;
        return true;
    }
}

因此，这是第二类，本身构成了重新组合。它由构造几种矩形的构造方法组成的构造器

public class Rectangle {
    public int width = 0;
    public int height = 0;
    public Point center;

    public Rectangle(Point center, int width, int height) {
        int x = 0;
        int y = 0;
        this.width=width;
        this.height=height;
        this.center=center;
    }

    public Point getTopLeft() {
        Point point = new Point(center.getX(), center.getY());
        point.moveRel(- width / 2, height / 2);
        return point;
    }

    public Point getBottomRight() {
        Point point = new Point(center.getX(), center.getY());
        point.moveRel(width / 2, - height / 2);
        return point;
    }

    public int getWidth() {

        return width;
    }


    public int getHeight() {

        return height;
    }
}

所以问题是似乎y轴以某种方式倒置，因为当我运行测试时，它返回了错误的值， () -> assertEquals(20, rect.getTopLeft().getY())，返回40（而不是20）并进行测试 () -> assertEquals(40, rect.getBottomRight().getY())返回2o而不是40。所以看来左上和右下点在y轴上是相反的。

Answer 1

您在moveRel中添加height / 2以获得topLeft。因此，正常情况下您得到40，而不是20。

似乎高度参数之前的符号错误：

public Point getTopLeft() {
    Point point = new Point(center.getX(), center.getY());
    point.moveRel(- width / 2, height / 2);
    return point;
}

public Point getBottomRight() {
    Point point = new Point(center.getX(), center.getY());
    point.moveRel(width / 2, - height / 2);
    return point;
}

Y轴在应形成矩形的代码中反转

1 个答案: