Question

当尝试用泡菜保存我的反应容器对象列表时，出现错误Command raised an exception: TypeError: cannot pickle 'TaskStepMethWrapper' object。我没有尝试任何操作，因为我不确定TaskStepMethWrapper是什么。这是我的代码：

@client.command()
async def reactionadd(ctx):
#  await ctx.send('Please give me the ID of the message you want to have a reactionrole on.')
#  msgid_var = await client.wait_for('message')
  await ctx.send('Please react with the emoji you want the reactionrole to use.')
  emoji_var = await client.wait_for('reaction_add')
#  await ctx.send('Please give me the ID of the role you want the reactionrole to give.')   
#  roleid_var = await client.wait_for('message')
  if not os.path.isfile('reactionrole.obj'):
    rrf = open('reactionrole.obj', 'xb')
    rrf.close()
  rrf = open('reactionrole.obj', 'rb+')
  if os.stat('reactionrole.obj').st_size == 0:
    rrobj = []
  else:
    rrobj = pickle.load(rrf)
  emoji_var = emoji_var[0]
  rrobj.append(reactionrole(749316751212150965, emoji_var, 749317419255857232))
  pickle.dump(rrobj, rrf)
  rrf.close()

class reactionrole:
    def __init__(self, msgid, emoji, roleid):
      self.msgid = msgid
      self.emoji = emoji
      self.roleid = roleid

那么，如何解决此错误？我应该继续使用pickle还是使用其他序列化技术？如果需要，我可以自己编写和解析文本文件。

Answer 1

结果emoji_var [0]是一个对象。只需使用str()将其转换为字符串即可解决此问题。

将咸菜用于不和谐的机器人时出错不和谐

1 个答案: