我有一个如下所示的MySQL表:
我想找到一个对表进行分组的查询,如下所示:
详细信息:
a_id
=地图上的分隔区域
is_flag
= 1-如果传感器在区域内/ 0-如果传感器不在区域内
基本上,第一张表描述了每个时间戳我的传感器在哪个区域。
第二张表告诉我传感器停留在每个区域内的时间。
我对每个area_id使用以下查询,并带有union all,以便在单个表中输出传感器在区域之间的移动时间以及每个区域内/下的停留时间。
select t.a_id, min(t.timestamp) starttime,max(t.timestamp) endtime,
t.is_flag from(SELECT *,
ROW_NUMBER() OVER(ORDER BY a.timestamp) - ROW_NUMBER() OVER(PARTITION BY
a.is_flag ORDER BY a.timestamp) as GRP
FROM tablename a where areas_id=25 ) t
group by is_flag , GRP, a_id
这是我的dbfiddle:https://www.db-fiddle.com/f/5pHiYKyx4yHoirRbGX4kP4/0
我的查询可以满足我的需求,但需要花费一整天的时间。
答案 0 :(得分:6)
WITH
cte1 AS (SELECT CAST(JSON_UNQUOTE(`timestamp`) AS DATETIME) ts,
areas_id,
is_in_or_out
FROM inouts),
cte2 AS (SELECT ts,
areas_id,
is_in_or_out,
CAST(ROW_NUMBER() OVER (PARTITION BY areas_id ORDER BY ts ASC) AS SIGNED)
-CAST(ROW_NUMBER() OVER (PARTITION BY areas_id ORDER BY is_in_or_out, ts ASC) AS SIGNED) AS grp
FROM cte1)
SELECT areas_id,
ANY_VALUE(is_in_or_out) is_in_or_out,
MIN(ts) min_ts,
MAX(ts) max_ts
FROM cte2
GROUP BY areas_id,
grp
ORDER BY areas_id, min_ts;
PS1。源数据略有更改。
PS2。 MySQL中需要CAST
,因为ROW_NUMBER()
会产生未签名的bigint。可以替换为0.0 + ...
。
答案 1 :(得分:2)
这是sql server的语法,但在主要dbms中应该相同
with
x as (
-- find start/end of each period
select areas_id, is_in_or_out is_flag, timestamp t1
, ISNULL(ABS(is_in_or_out - LAG(is_in_or_out, 1) over (partition by areas_id order by timestamp)), 1) T_START
, ISNULL(ABS(is_in_or_out - LEAD(is_in_or_out, 1) over (partition by areas_id order by timestamp)), 1) T_END
from inouts
),
y as (
select *, LEAD(t1, 1) over (partition by areas_id order by t1) t2
from x
WHERE T_START<>0 OR T_END<>0
)
select areas_id, is_flag, t1 starttime, t2 endtime
from y
WHERE T_START<>0
order by areas_id, t1
应该做到这一点
答案 2 :(得分:0)
更多信息(例如示例数据和失败的查询)将有所帮助,但看来您可以将其分组。
select a_id, is_flag, min(timestamp) as starttime, max(timestamp) as endtime
from tablename
group by a_id, is_flag
答案 3 :(得分:-1)
我在这里想念什么?您是否可能“思想过度”?下面的SQL提供与示例db-fiddle相同的结果集(我在副本上进行了测试),非常简单,并且运行速度更快。它为每个areas_id / is_in_or_out组合(按GROUP BY)给出一行。我不太明白为什么您需要UNION和ROW_NUMBER()OVER来使查询复杂化。希望这可以帮助。自己尝试一下,让我知道是否有任何问题!
SELECT areas_id,
starttime,
endtime,
is_in_or_out
FROM (SELECT areas_id,
MIN(timestamp) starttime,
MAX(timestamp) endtime,
is_in_or_out
FROM inouts
GROUP BY is_in_or_out,
areas_id) x
ORDER BY starttime;
P.S。我认为MBeale的解决方案实际上也是正确的(尽管它错过了ORDER BY)。