Question

课程：

public class Department
{
    public string Name { get; set; }
}

public class DepartmentA : Department
{
    public string NameA { get; set; }
}

public class Employee
{
    public string Name { get; set; }
    public int Salary { get; set; }
    public string Address { get; set; }
    public Department Department { get; set; }
}

public class EmployeeDTO
{
    public string Name { get; set; }
    public int Salary { get; set; }
    public string Address { get; set; }
    public Department Department { get; set; }
}

代码：

DepartmentA departmentA = new DepartmentA { NameA = "depA", Name = "dep" };

Employee emp = new Employee
{
        Name = "James",
        Salary = 20000,
        Address = "London",
        Department = departmentA
};
        
//Mapster
var empDTO = emp.Adapt<EmployeeDTO>();

//AutoMapper
//var config = new MapperConfiguration(cfg => cfg.CreateMap<Employee, EmployeeDTO>());

//var mapper = config.CreateMapper();
//EmployeeDTO empDTO = mapper.Map<EmployeeDTO>(emp);

Console.WriteLine("SourceType:" + emp.Department.GetType().Name);

Console.WriteLine("DestType:" + empDTO.Department.GetType().Name);

如果运行代码，您将看到SourceType和DestType不相同。我如何实现它们相同？ Mapster将部门划分为部门类（祖先）而不是部门A类（后代）。

在此示例中，我知道emp.Department中有后代，但在我的应用程序中我不知道。因此，此问题的解决方案必须是通用的。

~~我试图在AutoMapper中解决此问题。得到了相同的结果。~~如下面的@Prolog所述，在AutoMapper中工作。我更新了主代码。

如果有人解决了Mapster中的问题，我仍然很感兴趣。

Answer 1

您需要使用ShallowCopyForSameType，AutoMapper将仅执行深度复制声明的类型，Mapster将对所有类型执行深度复制。

Mapster-映射基类的后代类

1 个答案: