Question

我有一个包含健身房的物件，上面有可用的设备：

        const gyms = [
  {
    "name": "gym1",
    "equipmentAvailable": ["nothing"]
  },
  {
    "name": "gym2",
    "equipmentAvailable": ["jump rope","stationary bike","barbell"]
  },
  {
    "name": "gym3",
    "equipmentAvailable": ["kettlebell","dumbbell"]
  },
  {
    "name": "gym4",
    "equipmentAvailable": ["barbell","kettlebell","jump rope"]
  }
]

我还获得了下一个锻炼所需的设备清单（然后将其转换为Set）：

const availableNeeded = ["barbell","jump rope"]

const equipmentSet = new Set(availableNeeded);

当前，我正在使用.find（）拉出第一个符合我的设备需求的健身馆，

const filteredWorkouts = gyms.find(workout => (
  workout.equipmentAvailable.some(equipment => equipmentSet.has(equipment))
))

console.log(filteredWorkouts)

自然，这总是返回Gym2，因为它是第一个与所需设备匹配的健身房。但是，有时我想将其切换到gym4，因为它也具有所需的设备，但是find（）无法提供。

我应该如何将Gym输出随机化，以便可以输出Gym2 或 Gym4？

Answer 1

使用.filter而不是.find来获取可能匹配的数组，然后从该数组中获取随机元素：

const gyms = [
  {
    "name": "gym1",
    "equipmentAvailable": ["nothing"]
  },
  {
    "name": "gym2",
    "equipmentAvailable": ["jump rope","stationary bike","barbell"]
  },
  {
    "name": "gym3",
    "equipmentAvailable": ["kettlebell","dumbbell"]
  },
  {
    "name": "gym4",
    "equipmentAvailable": ["barbell","kettlebell","jump rope"]
  }
];
const availableNeeded = ["barbell","jump rope"];
const filteredWorkouts = gyms.filter(gym => (
  availableNeeded.every(equip => gym.equipmentAvailable.includes(equip))
));
const result = filteredWorkouts[Math.floor(Math.random() * filteredWorkouts.length)];
console.log(result);

有没有一种方法可以从包含特定值的对象中查找（）随机元素

1 个答案: