Question

我正在尝试制作一个机器人，该机器人会列出加入队伍进行突袭的玩家名单。当您键入！join 时，应该将您添加到playerlist数组中（按预期工作）。然后，我想将分配给该数组的值作为字段嵌入不和谐消息中。当您键入！fireteam 时，它应显示嵌入内容，其中显示了键入！join 的每个用户名。几乎按预期工作，我唯一的问题是，每当有人键入join命令时，它都会再次添加整个数组，而不是最新添加的数组。

const Discord = require('discord.js');
const { prefix, token } = require('./config.json');
const { default: Collection } = require('@discordjs/collection');

const client = new Discord.Client();

const playerlist = [];


const pListEmbed = new Discord.MessageEmbed()
.setColor('#3CB371')
.setTitle('RAID')
.addFields(
    {name: 'Fireteam', value: "Players who have joined: ", inline: true}
)


function joinpug(message) {
    if(playerlist.length <= 5){
    playerlist.push(message.author.username)
    console.log(playerlist);

    pListEmbed.addFields({name: "Player", value: `**${playerlist}**` + " ", inline: true})

    }else{
        message.channel.send(pListEmbed)}
}


client.once('ready', () => {
    console.log('Ready!');
});


client.on('message', message => {
    if (!message.content.startsWith(prefix) || message.author.bot) return;

    const args = message.content.slice(prefix.length).split(/ +/);
    const command = args.shift().toLowerCase();

    if (command === 'join') {
        joinpug(message);
    } else if(command=== `fireteam`){
        message.channel.send(pListEmbed);
    }

});


client.login('');

很抱歉，如果这是一个简单的问题，我对JS还是陌生的。

Answer 1

好吧，如果我没记错的话，您的问题在于重复值，那么快速解决方案是在您的Set上使用joinpug

function joinpug(message) {
    if(playerlist.length <= 5){
    playerlist = playerlis.push(message.author.username)
    playerlist = [...new Set(playerlist)] ;
    console.log(playerlist);

    pListEmbed.addFields({name: "Player", value: `**${playerlist}**` + " ", inline: true})

    }else{
        message.channel.send(pListEmbed)}
}

Answer 2

每次创建新字段时，您都在字段中添加playerlist作为该字段的值，这样它会添加整个数组，而您应该像这样添加作者的姓名

pListEmbed.addFields({name: "Player", value: `**${message.author.name}**` + " ", inline: true})

将数组的值用作不和谐嵌入的值

2 个答案: