Question

我正在用Java构建一个应用程序，以等待服务器的请求。

应用程序在端口6868上启动新的服务器侦听器，并等待JSON格式的请求正文

private static void startListening() {
        try (ServerSocket serverSocket = new ServerSocket(6868)) {
            System.out.println("Server is listening on port " + 6868);
            while (!done) {
                Socket socket = serverSocket.accept();  //Accepting the request
                InputStream input = socket.getInputStream();
                BufferedReader reader = new BufferedReader(new InputStreamReader(input));
                Scanner sc = new Scanner(new InputStreamReader(input));  //Get the request and convert to a string
                String inline = "";
                while(sc.hasNext())
                {
                    inline = inline + sc.nextLine();
                }
                System.out.println("JSON in data context:");  //Print the JSON request
                System.out.println(inline);
                sc.close();
            }
            
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

我在这里有两个问题：

当我打印结果时，我得到了：

System.print结果：

POST / HTTP/1.1Host: localhost:6868User-Agent: Mozilla/5.0 (Windows NT 6.1; rv:79.0) Gecko/20100101 Firefox/79.0Accept: */*Accept-Language: es-MX,es;q=0.8,en-US;q=0.5,en;q=0.3Accept-Encoding: gzip, deflateContent-Type: text/plain;charset=UTF-8Content-Length: 759Origin: http://localhost:4200Connection: keep-aliveReferer: http://localhost:4200/cliente/adm/fiscalprinter{"requests":[{"cmd":2}],"modelo":27,"puerto":7,"baudios":9600}

如您所见，我不仅在json中获取请求的主体，还获取与来自服务器的服务器相关的所有数据。

我该怎么做才能仅获取请求的json正文？

如何将响应发送到即将发出此请求的服务器？因为服务器正在等待永远不会收到的响应...

希望您能帮助我，谢谢！

编辑：

这是打字稿angular的函数，它将请求发送到我的Java应用程序：

host = "localhost";
http = new XMLHttpRequest();

async sendData(request) {
        var url = null;
        url = "http://" + this.host +  ":6868";
        this.http.open("POST", url, false);
        this.http.onreadystatechange = function() {
        if (this.readyState == 4 && this.status == 200) {
            var resultado = JSON.parse(this.responseText);
            var errorCode = resultado.result.code;
            var errorDesc = resultado.result.description;
            var lastResponse = null;
            if (typeof(resultado.description) != 'undefined'){
                lastResponse = resultado;
            } else {
                lastResponse = null;
                }
            }
        };

        var stringData = JSON.stringify(request);
        this.http.send(stringData);

        return this.lastResponse;
    }

如何等待JSON发布请求并发送响应Java

0 个答案: