我有此词典列表,数据,我想应用分组依据,然后金额总和,但是我得到的截止日期为{{ 1}},而不是最终聚合中的2020-05-11 00:00:00+00
请指出我做错了什么地方。
输入数据:-
2020-05-17 00:00:00+00
预期结果:-
data = [
{start_date: "2020-05-11 00:00:00+00", end_date: "2020-05-17 00:00:00+00", id: "ola", amount: 10},
{start_date: "2020-05-11 00:00:00+00", end_date: "2020-05-17 00:00:00+00", id: "ola", amount: 2}
]
当前结果:-
start_date: "2020-05-11 00:00:00+00", end_date: "2020-05-17 00:00:00+00", amount: 12}
分组依据公式:-
start_date: "2020-05-11 00:00:00+00", end_date: "2020-05-11 00:00:00+00", amount: 12}
如果还有其他使用Javascript的解决方案,请提出建议。谢谢
答案 0 :(得分:1)
因为要链接data
,所以下一个groupBy
只需要采用一个参数(即doc中的变换键的迭代器)
您可以设置start_date
和end_date
组合的组密钥
const data = [
{
start_date: "2020-05-11 00:00:00+00",
end_date: "2020-05-17 00:00:00+00",
id: "ola",
amount: 10,
},
{
start_date: "2020-05-11 00:00:00+00",
end_date: "2020-05-17 00:00:00+00",
id: "ola",
amount: 2,
},
]
const result = _(data)
.groupBy((obj) => [obj.start_date, obj.end_date].join("to"))
.map((value, key) => ({
start_date: key.split("to")[0],
end_date: key.split("to")[1],
amount: _.sumBy(value, "amount"),
}))
.value()
console.log(result)
<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.20/lodash.min.js"></script>
答案 1 :(得分:1)
使用开始和结束作为键的简单化简循环
data = [{
start_date: "2020-05-11 00:00:00+00",
end_date: "2020-05-17 00:00:00+00",
id: "ola",
amount: 10
},
{
start_date: "2020-05-11 00:00:00+00",
end_date: "2020-05-17 00:00:00+00",
id: "ola",
amount: 2
}
]
const groupIt = data => {
const groupings = data.reduce((grps, item) => {
const { start_date, end_date, amount } = item;
const key = `${start_date}-${end_date}`;
grps[key] = grps[key] || { start_date, end_date, amount: 0 };
grps[key].amount += amount;
return grps;
}, {});
return Object.values(groupings);
}
const result = groupIt(data);
console.log(result);