Question

我有两个列表，我正在尝试根据数字出现的次数来创建数字的多个副本。

numbers = [0, 1, 2]
amount = [1, 2, 3]

我尝试过：

total = []
n = 0
for i in range(len(numbers)):
    product = numbers[n] * amount[n]
    n += 1
    total.extend(product)

但是我得到了错误：

TypeError: 'int' object is not iterable.

我的预期输出是：

total = [0, 1, 1, 2, 2, 2]

Answer 1

使用zip

// thread 1
a->name = "Bar";
// thread 2
Dog* d = static_cast<Dog*>(a);

result = []
for i, j in zip(numbers, amount):
    result.extend([i] * j)

print(result)

Answer 2

您的错误在行内：

product = numbers[n] * amount[n]

它不会产生列表，而是一个整数。因为您要将两个数字相乘。

您真正想要的是

product = [numbers[n]] * amount[n]