WordPress自定义帖子元JSON字符串将不会与json_decode()解码

时间:2011-06-15 14:28:27

标签: php string json wordpress decode

我有一个关于从WordPress自定义帖子元获取的JSON字符串的问题。

1)我抓住自定义帖子元并将其保存为$json1

$json1 = get_post_meta(get_the_ID(), 'netr_locations_json', true);

2)我保存与$json2相同的字符串,这次硬编码。

$json2 = '{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}';

3)我回应了弦乐。它们完全相同。

echo $json1;
echo $json2;

结果:

{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}

{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}

4)我var_dump解码后的字符串。 WordPress中的字符串不会解码并产生NULL,即使它是相同的字符串。硬编码字符串解码得很好。

var_dump(json_decode($json1));
var_dump(json_decode($json2));

结果:

NULL

object(stdClass)#177 (1) { ["locations"]=> array(1) { [0]=> object(stdClass)#173 (6) { ["number"]=> int(1) ["header"]=> string(15) "This is a title" ["desc"]=> string(22) "This is a description." ["address"]=> string(23) "Infinity Loop Cupertino" ["lat"]=> string(10) "37.3322024" ["lng"]=> string(11) "-122.030755" } } } 

我错过了什么? WordPress中的字符串出了什么问题?


更新

var_dump($json1)给出了这个:

string(282) "{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}" 

var_dump($json2)给出了这个:

string(162) "{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}"

字符串后的整数是什么意思?


更新 这是hex_dump()

的结果

$ json1:

00 000 22 7B 26 71 75 6F 74 3B 6C 6F 63 61 74 69 6F 6E "{" location
10 016 73 26 71 75 6F 74 3B 3A 5B 7B 26 71 75 6F 74 3B s": [{"
20 032 6E 75 6D 62 65 72 26 71 75 6F 74 3B 3A 31 2C 26 number&q uot;:1,& 
30 048 71 75 6F 74 3B 68 65 61 64 65 72 26 71 75 6F 74 quot;hea der" 
40 064 3B 3A 26 71 75 6F 74 3B 54 68 69 73 20 69 73 20 ;:" This is 
50 080 61 20 74 69 74 6C 65 26 71 75 6F 74 3B 2C 26 71 a title& quot;,&q 
60 096 75 6F 74 3B 64 65 73 63 26 71 75 6F 74 3B 3A 26 uot;desc ":& 
70 112 71 75 6F 74 3B 54 68 69 73 20 69 73 20 61 20 64 quot;Thi s is a d 
80 128 65 73 63 72 69 70 74 69 6F 6E 2E 26 71 75 6F 74 escripti on." 
90 144 3B 2C 26 71 75 6F 74 3B 61 64 64 72 65 73 73 26 ;," address& 
A0 160 71 75 6F 74 3B 3A 26 71 75 6F 74 3B 49 6E 66 69 quot;:&q uot;Infi 
B0 176 6E 69 74 79 20 4C 6F 6F 70 20 43 75 70 65 72 74 nity Loo p Cupert 
C0 192 69 6E 6F 26 71 75 6F 74 3B 2C 26 71 75 6F 74 3B ino" ;," 
D0 208 6C 61 74 26 71 75 6F 74 3B 3A 26 71 75 6F 74 3B lat" ;:" 
E0 224 33 37 2E 33 33 32 32 30 32 34 26 71 75 6F 74 3B 37.33220 24" 
F0 240 2C 26 71 75 6F 74 3B 6C 6E 67 26 71 75 6F 74 3B ,"l ng" 
100 256 3A 26 71 75 6F 74 3B 2D 31 32 32 2E 30 33 30 37 :"- 122.0307 
110 272 35 35 26 71 75 6F 74 3B 7D 5D 7D 22 55" }]}"

$ json2:

00 000 7B 22 6C 6F 63 61 74 69 6F 6E 73 22 3A 5B 7B 22 {"locati ons":[{" 
10 016 6E 75 6D 62 65 72 22 3A 31 2C 22 68 65 61 64 65 number": 1,"heade 
20 032 72 22 3A 22 54 68 69 73 20 69 73 20 61 20 74 69 r":"This is a ti 
30 048 74 6C 65 22 2C 22 64 65 73 63 22 3A 22 54 68 69 tle","de sc":"Thi 
40 064 73 20 69 73 20 61 20 64 65 73 63 72 69 70 74 69 s is a d escripti 
50 080 6F 6E 2E 22 2C 22 61 64 64 72 65 73 73 22 3A 22 on.","ad dress":" 
60 096 49 6E 66 69 6E 69 74 79 20 4C 6F 6F 70 20 43 75 Infinity Loop Cu 
70 112 70 65 72 74 69 6E 6F 22 2C 22 6C 61 74 22 3A 22 pertino" ,"lat":" 
80 128 33 37 2E 33 33 32 32 30 32 34 22 2C 22 6C 6E 67 37.33220 24","lng 
90 144 22 3A 22 2D 31 32 32 2E 30 33 30 37 35 35 22 7D ":"-122. 030755"} 
A0 160 5D 7D ]} 

所以显然存在差异。


这是完整的代码:

$json1 = get_post_meta(get_the_ID(), 'netr_locations_json', true);
$json2 = '{"locations":[{"number":1,"header":"This is a title","desc":"This is a description.","address":"Infinity Loop Cupertino","lat":"37.3322024","lng":"-122.030755"}]}';

echo $json1;
echo '<br/><br/>';
echo $json2;
echo '<br/><br/>';

var_dump(json_decode($json1));
echo '<br/><br/>';
var_dump(json_decode($json2));

感谢您一看。

4 个答案:

答案 0 :(得分:2)

使用echo来比较字符串并不真正起作用。我建议你也把字符串转换成十六进制值。见here for a hex_dump php routine。通过这种方式,您将看到它们的不同之处,可以方便地跟踪编码问题。

json_decode仅适用于UTF-8编码数据。我假设您传递给字符串的数据不会验证UTF-8,因此不能引用任何值。

您必须先将数据正确编码为UTF-8,然后才能使用它。为此,您必须了解数据的编码。

要验证字符串是否为有效的UTF-8数据,我在问题SimpleXML and Chinese中发布了一些代码。这是一个名为can_be_valid_utf8_statemachine()的函数。

在可能的编码问题旁边,当您比较这两个值时,请在浏览器中同时显示输出时要小心。这里有一些“浏览器兼容”输出:

echo '<pre>', htmlspecialchars($json1), '</pre>';
echo '<pre>', htmlspecialchars($json2), '</pre>';

如果你用字符串执行此操作,它应该根据您添加到问题中的hex_dump()输出显示json被破坏的位置。

答案 1 :(得分:1)

可能会转义$json1字符串...尝试

var_dump(json_decode(stripslashes($json1)));

答案 2 :(得分:0)

str_replace('\\','',$_POST['you-param']);

答案 3 :(得分:0)

如果stripslashes不适合您,请尝试sails-hook-autoreload

例如:str_replace('\\','',$meta_value)