正确显示mySQL一对多查询的结果

Question

我有两张桌子：

      TRIPS
-----------------
tripID | clientID

和

              LEGS
--------------------------------
legID | depart | arrive | tripID

TRIPS与LEGS有一对多的关系，因为每legID有几个tripID个。{我需要以下列格式显示它们：

Trip tripID1:
    Leg legID1: depart1 - arrive1
    Leg legID2: depart2 - arrive2

Trip tripID2:
    Leg legID3: depart3 - arrive3
    Leg legID4: depart4 - arrive4

etc...

我已经能够通过WHILE()循环遍历legIDs，但是我在TRIPS循环中嵌入LEGS循环时遇到了麻烦。我的疑问是：

<?php
$legsQuery = "SELECT  trips.tripID, legs.depart, legs.arrive FROM legs, trips WHERE `trips`.tripID = `legs`.tripID";
$legsQueryResult = mysql_query($legsQuery) or die("QUERY LEG ERROR: " . mysql_error());
while($row = mysql_fetch_assoc($legsQueryResult)) {
    print_r($row);
}
?>

Answer 1

1. 添加order by子句以按行程ID排序
2. 创建$lastTripID变量以检查何时从“新旅行”获得“腿”
3. [推荐]使用join从多个表中选择数据

代码：

<?php
    $legsQuery = "
        select  
            trips.tripID, 
            legs.depart, 
            legs.arrive 
        from 
            legs
            inner join trips on trips.tripID = legs.tripID
        order by
            trips.tripID
    ";
    $legsQueryResult = mysql_query($legsQuery) or die("QUERY LEG ERROR: " . mysql_error());
    $lastTripID = null;
    while ($row = mysql_fetch_assoc($legsQueryResult)) {
        if ( $row['tripID'] !== $lastTripID ) {
            echo $row['tripID'], "\n";
            $lastTripID = $row['tripID'];
        }
        print_r($row);
    }