Question

我正在尝试删除列表中相同元组内存在的重复元素

list_1= [('nissan', 'nissan'), ('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]

我想要的输出是：

list_1= [('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]

我尝试使用“ set”，但是它只会删除重复的元组！

Answer 1

您可以使用列表理解，这意味着通过迭代现有列表来生成新列表（可能按条件过滤）：

TimeZone.getTimeZone("GMT+03")

Answer 2

请参见

<template>
  <div class="connections">
    <canvas id="pixi"></canvas>
  </div>
</template>

<script>
import * as PIXI from 'pixi.js'

export default {
  name: 'ConnectionsLayer',
 
  methods: {
    drawPixi() {
      var canvas = document.getElementById('pixi')

      const app = new PIXI.Application({
        width: window.innerWidth,
        height: window.innerHeight,
        antialias: true,
        transparent: true,
        view: canvas,
      })

      let graphics = new PIXI.Graphics() 
      graphics.lineStyle(8, 0x000000)

      //start
      graphics.moveTo(300, 250)
      //end
      graphics.lineTo(500, 250)

      app.stage.addChild(graphics)
    },
  },

  mounted() {
    this.drawPixi()
  },
}
``

输出

lst = [('nissan', 'nissan'), ('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]
no_dups = [x for x in lst if x[0] != x[1]]
print(no_dups)

Answer 3

使用set

可以轻松解决

list_1= [('nissan', 'nissan'), ('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]
res=[]
for i in list_1:
    if len(set(i)) == 2:
        res.append(i)
print(res)

Answer 4

使用filter：

list_1= [('nissan', 'nissan'), ('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]

list_no_duplicates = list(filter(lambda x: x[0] != x[1], list_1))

print(list_no_duplicates)
# [('buy', 'toyota'), ('sale', 'toyota'), ('cheap', 'toyota')]

Answer 5

您提到的输出与问题中的输出不同

但是如果您想删除列表中同一元组内存在的重复元素，可以通过 list_1 = [x for x in [tuple(set(item)) for item in list_1]]

给出输出 [('nissan',), ('buy', 'toyota'), ('toyota', 'sale'), ('cheap', 'toyota')]

删除元组列表中的重复元素

5 个答案: