如何使用JQuery定位变量的子项

Question

如何定位 post_ad_cloned的输入子项？

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone().removeClass('duplicate_name').appendTo('#sss').show();
$("post_ad_cloned input").css('color', 'red'); 

Answer 1

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone().removeClass('duplicate_name').appendTo('#sss').show();
$("input", post_ad_cloned).css('color', 'red'); 

或：

var post_ad = $('.duplicate_name'); 
var post_ad_cloned = post_ad.clone()
  .removeClass('duplicate_name')
  .appendTo('#sss')
  .show()
  .children('input')
    .css('color', 'red');