Question

您好，

我有以下代码从当前AD创建树：

public static ActiveDirectory GetActiveDirectoryTree(string pathToAD = "")
{
    DirectoryEntry objADAM = default(DirectoryEntry);
    // Binding object. 
    DirectoryEntry objGroupEntry = default(DirectoryEntry);
    // Group Results. 
    DirectorySearcher objSearchADAM = default(DirectorySearcher);
    // Search object. 
    SearchResultCollection objSearchResults = default(SearchResultCollection);
    // Binding path. 
    ActiveDirectory result = new ActiveDirectory();
    ActiveDirectoryItem treeNode;

    // Get the AD LDS object. 
    try
    {
        if (pathToAD.Length > 0)
            objADAM = new DirectoryEntry();
        else
            objADAM = new DirectoryEntry(pathToAD);
        objADAM.RefreshCache();
    }
    catch (Exception e)
    {
        throw e;
    }

    // Get search object, specify filter and scope, 
    // perform search. 
    try
    {
        objSearchADAM = new DirectorySearcher(objADAM);
        objSearchADAM.Filter = "(&(objectClass=group))";
        objSearchADAM.SearchScope = SearchScope.Subtree;
        objSearchResults = objSearchADAM.FindAll();
    }
    catch (Exception e)
    {
        throw e;
    }

    // Enumerate groups 
    try
    {
        if (objSearchResults.Count != 0)
        {
            //SearchResult objResult = default(SearchResult);
            foreach (SearchResult objResult in objSearchResults)
            {
                objGroupEntry = objResult.GetDirectoryEntry();
                result.ActiveDirectoryTree.Add(new ActiveDirectoryItem() { Id = objGroupEntry.Guid, ParentId = objGroupEntry.Parent.Guid, AccountName = objGroupEntry.Name, Type = ActiveDirectoryType.Group, PickableNode = false });

                foreach (object child in objGroupEntry.Properties["member"])
                {
                    treeNode = new ActiveDirectoryItem();
                    var path = "LDAP://" + child.ToString().Replace("/", "\\/");
                    using (var memberEntry = new DirectoryEntry(path))
                    {
                        if (memberEntry.Properties.Contains("sAMAccountName") && memberEntry.Properties.Contains("objectSid"))
                        {
                            treeNode.Id = Guid.NewGuid();
                            treeNode.ParentId = objGroupEntry.Guid;
                            treeNode.AccountName = memberEntry.Properties["sAMAccountName"][0].ToString();
                            treeNode.Type = ActiveDirectoryType.User;
                            treeNode.PickableNode = true;
                            treeNode.FullName = memberEntry.Properties["Name"][0].ToString();

                            byte[] sidBytes = (byte[])memberEntry.Properties["objectSid"][0];
                            treeNode.ObjectSid = new System.Security.Principal.SecurityIdentifier(sidBytes, 0).ToString();

                            result.ActiveDirectoryTree.Add(treeNode);
                        }
                    }
                }
            }
        }
        else
        {
            throw new Exception("No groups found");
        }
    }
    catch (Exception e)
    {
        throw new Exception(e.Message);
    }

    return result;
}

问题是使用（var memberEntry = new DirectoryEntry（path））将DomainUsers作为用户返回到此树，我不确定这是否正确？

假设我存储了DomainUsers节点的sidId，然后将其发送到以下方法：

public static Boolean GetActiveDirectoryName(string sidId,out string samAccountName,out string fullName)
        {
            samAccountName = string.Empty;
            fullName = string.Empty;


            if (sidId != null && sidId.Length > 0)
            {
                var ctx = new System.DirectoryServices.AccountManagement.PrincipalContext(ContextType.Domain, null);
                using (var up = UserPrincipal.FindByIdentity(ctx, IdentityType.Sid, sidId))
                {
                    samAccountName = up.SamAccountName;
                    fullName = up.Name;

                    return true;
                }
            }
            return false;
        }

up将被设置为null？如果我在AD中选择另一个用户，那么它工作得很好。我怀疑DomainUsers是一个组，但如何在DirectoryEntry上检查这个？

BestRegards

Answer 1

脱离我的头脑：您是否考虑过检查返回结果的Schema属性？我想你可以使用DirectoryEntry.SchemaEntry.Name轻松找出一组。如果您的架构条目是一个组，它应该返回group。

参考：MSDN: DirectoryEntry.SchemaEntry

<小时/> 只是出于好奇和上面代码中的一些主题：

 if (pathToAD.Length > 0)
      objADAM = new DirectoryEntry();
 else
      objADAM = new DirectoryEntry(pathToAD);
 objADAM.RefreshCache();

如果pathToAD？

，您不想使用Length>0吗？

Answer 2

警告：
接受的答案使用危险，因为DirectoryEntry.SchemaEntry.Name可能是任何东西。（有关更多详细信息，请参见here。

因此，最简单的方法是改为检查objectClass，如下所示：

// For group check
bool isGroup = entry.Properties["objectClass"]?.Contains("group") == true;
// For user check
bool isUser = entry.Properties["objectClass"]?.Contains("user") == true;

P.S。对于那些想知道我为什么使用== true的人，请参阅here

如何知道DirectoryEntry是用户还是组？

2 个答案: