Question

我正在使用它向服务器上的每个人发送dm，

@bot.command(pass_context = True)
@commands.has_permissions(manage_messages=True)
async def dm_all(ctx, *, args=None):
    sended_dms = 0
    rate_limit_for_dms = 20
    time_to_wait_to_avoid_rate_limit = 60

    if args != None:
        members = ctx.guild.members
        for member in members:
            try:
                await member.send(args)
                await ctx.channel.send(" sent to: " + member.name)

            except:
                await ctx.channel.send("Couldn't send to: " + member.name)
            sended_dms += 1
            if sended_dms % rate_limit_for_dms == 0: 
                asyncio.sleep(time_to_wait_to_avoid_rate_limit) 

    else:
        await ctx.channel.send("Please provide a message to send!")

代码很完美，它的工作也很好。它在将dm发送到{member.name}的每个dm之后发送日志，我想要的是在每个日志（即msg已发送到.....）之后，对于下一个日志，它应该编辑上一条消息。（对不起，我不好解释：p）

像这样在每个dm之后发送一条消息，发送到{member.name} 然后下一个发送到{member.name}

我想要的是它不应该一次又一次地发送它，而应该为每个dm一次又一次地编辑第一条消息。

如果能提供帮助，我将不胜感激！

Answer 1

您可以使用Message.edit。您可以通过以下方式在代码中使用它：

@client.command(pass_context = True)
@commands.has_permissions(manage_messages=True)
async def dm_all(ctx, *, args=None):
    sended_dms = 0
    rate_limit_for_dms = 20
    time_to_wait_to_avoid_rate_limit = 60

    if args != None:
        members = ctx.guild.members
        firstTime = True
        msg = None
        for member in members:
            if not member.bot:
                try:
                    await member.send(args)
                    if firstTime:
                        msg = await ctx.channel.send(" sent to: " + member.name)
                        firstTime = False
                    else:
                        await msg.edit(content=" sent to: " + member.name)
                except Exception as e:
                    await msg.edit(content="Couldn't send to: " + member.name)
                if sended_dms % rate_limit_for_dms == 0: 
                    await asyncio.sleep(time_to_wait_to_avoid_rate_limit) 
    else:
        await ctx.channel.send("Please provide a message to send!")

还添加了一行以忽略漫游器用户。

Answer 2

要编辑消息，可以使用Message.edit。这是一个示例：

random_message = await ctx.send("old message")
await random_message.edit("new message")

此外，如果您查看documentation或其他stackoverflow问题，也可以轻松找到答案。

如何在Discord.py中编辑消息？

2 个答案: