Question

我正在尝试将所有联系人都放在Android联系人的收藏夹列表中。目前，我可以获取所有组ID，包括最喜欢的组ID。但似乎没有联系人将组ID作为最喜欢的组ID。

我正在尝试获取每个组中的所有组ID和联系人。打印两个列表后，我发现收藏夹的组ID不在联系人列表中

ArrayList<String> favGroupId=new ArrayList<String>();
        final String[] GROUP_PROJECTION = new String[] {
                ContactsContract.Groups._ID, ContactsContract.Groups.TITLE };
        Cursor  cursor = getContentResolver().query(
        ContactsContract.Groups.CONTENT_URI, GROUP_PROJECTION, null,
                null, ContactsContract.Groups.TITLE);

        while (cursor.moveToNext()) {
            String id = cursor.getString(cursor
                    .getColumnIndex(ContactsContract.Groups._ID));
            Log.v("Test",id);

            String gTitle = (cursor.getString(cursor
                    .getColumnIndex(ContactsContract.Groups.TITLE)));

            Log.v("Test",gTitle);
            if (gTitle.contains("Favorite_")) {
                gTitle = "Favorites";
                favGroupId.add(id);
            }
        }
        cursor.close();

Answer 1

您可以使用STARRED课程中的ContactsContract.Contact字段。如果您将查询更改为：

Cursor cursor = this.managedQuery(
    ContactsContract.Contacts.CONTENT_URI, projection, "starred=?",
    new String[] {"1"}, null);

这应返回Android上默认通讯录应用中“收藏夹”标签中显示的所有联系人列表。

Answer 2

完整答案，包括用于打开与意图的联系的intentUriString：

Map getFavoriteContacts(){

    Map contactMap = new HashMap();

    Uri queryUri = ContactsContract.Contacts.CONTENT_URI;

    String[] projection = new String[] {
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.Contacts.STARRED};

    String selection =ContactsContract.Contacts.STARRED + "='1'";

    Cursor cursor = managedQuery(queryUri, projection, selection, null, null);

    while (cursor.moveToNext()) {
        String contactID = cursor.getString(cursor
                .getColumnIndex(ContactsContract.Contacts._ID));

        Intent intent = new Intent(Intent.ACTION_VIEW);
        Uri uri = Uri.withAppendedPath(
            ContactsContract.Contacts.CONTENT_URI, String.valueOf(contactID));
        intent.setData(uri);
        String intentUriString = intent.toUri(0);

        String title = (cursor.getString(
            cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME)));

        contactMap.put(title,intentUriString);
    }

    cursor.close();
    return contactMap;
}

Answer 3

Ty与Kotlin：

import android.content.Context
import android.provider.ContactsContract
import android.content.Intent
import android.net.Uri


fun getFavoriteContacts(context: Context): Map<*, *> {

    lateinit var contactMap : HashMap<String, String>

    val queryUri = ContactsContract.Contacts.CONTENT_URI.buildUpon()
            .appendQueryParameter(ContactsContract.Contacts.EXTRA_ADDRESS_BOOK_INDEX, "true")
            .build()

    val projection = arrayOf(
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.Contacts.STARRED
    )

    val selection = ContactsContract.Contacts.STARRED + "='1'"

    val cursor = context.getContentResolver().query(queryUri,
            projection, selection, null, null)

    while (cursor.moveToNext()) {
        val contactID = cursor.getString(cursor
                .getColumnIndex(ContactsContract.Contacts._ID))

        val intent = Intent(Intent.ACTION_VIEW)
        val uri = Uri.withAppendedPath(
                ContactsContract.Contacts.CONTENT_URI, contactID.toString())
        intent.data = uri
        val intentUriString = intent.toUri(0)

        val title = cursor.getString(
                cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME))

        contactMap[title] = intentUriString
    }

    cursor.close()
    return contactMap
}

在Android中获取收藏联系人

3 个答案: